There are
ways of selecting two of the six blocks at random. The probability that one of them contains an error is
So
has probability mass function
These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.
The expected value of finding an error is then
Let's start with the area of the square
now let's subtract the are of the two half circles.
two half circles are the same as one circle, and we know that the diameter of the circle is 8 (same as the side of a square) so it's radius is 8/2= 4 inches
now we just subtract and our answer is
I'll write "x" instead theta.
sin x + 1 = cos(2x)
formula: cos(2x) = 1 - 2sin²x
sin x + 1 = 1 - 2sin²x
2sin²x + sin x = 0
sin x (2sin x + 1) = 0
sin x = 0 or sin x = -1/2
x1 = πk and x2 = -π/6 + 2πk and
x3 = 5π/6 + 2πk
for domain 0≤x<2π :
x1 = 0 (for k=0 in x1)
x2 = π (for k=1 in x1
x3 = 11π/6 (for k=1 in x2)
x4 = 5π/6 (for k=0 in x3).
k is an integral.
Answer:
$0.40 per minute
Step-by-step explanation:
You divide 6.40 by 16 to get 0.40.
To fact check this, I multiplied 0.40 by 16 and got 6.40.
Answer:
-3y^2 + y + 100
Step-by-step explanation:
Combine like terms.
-3y+4y = 1y or "y"
Add "y" back into the equation.
-3y^2 + y + 100
The equation cannot be simplified any further.
I hope this helped!
