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3 years ago

The distance between -34 and 14

Mathematics

2 answers:

Sphinxa [80]3 years ago

8 0

I think it would be -27
As I believe you need to add -34 and 14 then divide by 2

bogdanovich [222]3 years ago

4 0

The difference between-34 and 14 is 48
(-34)-(+14)=-48
|-48|=
=48

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3 years ago

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

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4 years ago

You are playing a game where you draw a card from a standard deck, and you will win $13 if you draw a face card,

marissa [1.9K]

Answer:

Step-by-step explanation:

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There are 3 face cards / suit. Every suit contains a Jack, Queen, and king.

There are 4 suits so the number of face cards is 3*4 = 12

There is 1 ace / suit

There are 4 suits so the number of aces is 1 * 4 = 4

The gain from the face cards = 12 * 13 = 156

The gain from the aces = 4 * 3 = 12

Total gain = 168

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Any other card costs you $5

How many cards is that? 52 - 16 = 36

Each one costs 5 dollars

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So each time you play the game, you can expect to lose 180 - 68 = 12 dollars. You should walk away quickly from this one.

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2 years ago

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3 years ago

Use summation notation to write the series 49 + 54 + 59 +... for 14 terms.

My name is Ann [436]

Answer:

Arithmetic sequence states that a sequence of numbers such that the difference between the consecutive terms is constant.

it is given by: $a_n = a+(n-1)d$ where a is the first term , n is the number of term and d is the common difference.

Given the series: $49 + 54 + 59+ ......$

here, Common difference(d) = 5

First term(a) = 49

by definition we have;

For nth term

$a_n = a+(n-1)d$

$a_n = 49+(n-1)5$

$a_n =49+5n -5$ = 5n + 44

To write the series using summation notation for 14 terms

Summation symbol $'\sum'$

The series for 14th terms is given by;

$\sum_{n=1}^{14}(5n +44)$

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3 years ago

Read 2 more answers