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Gemiola [76]
3 years ago
12

Pleaseee help, I’m rubbish at maths :/

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
3 0

Answer:

4 row: 6,5,7,5

5 row: 6,8

6 row: 5,4,6,4

For 7: 4/25

For greater than 7: 1/25

Step-by-step explanation:

Total is 25

For 7: 4/25

For greater than 7: 1/25

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Which method is used in elimination to find the solutions of x + 3y = 9 and x - 3y = 8?
weqwewe [10]

Answer:

x=17/2  y=1/6

Step-by-step explanation:

-1(x+3y=9)

1(x-3y=8)

_________

-x-3y=-9

x-3y=8

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-6y/6=-1/6   y=1/6

x+3(1/6)=9

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   - 1/2  - 1/2

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4 0
3 years ago
15 points please help
Molodets [167]
The answer is x= -21

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7 0
3 years ago
(2^8 x 3^−5 x 6^0)−2 x 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 x 2^28
Veronika [31]

(2^8\cdot3^{-5}\cdot6^0)^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot2^{28}\\\\=(2^8)^{-2}\cdot(3^{-5})^{-2}\cdot1^{-2}\cdot\dfrac{(3^{-2})^4}{(2^3)^4}\cdot2^{28}\\\\=2^{-16}\cdot3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot2^{28}\\\\=2^{-16}\cdot2^{28}\cdot2^{-12}\cdot3^{10}\cdot3^{-8}\\\\=2^{-16+28+(-12)}\cdot3^{10+(-8)}\\\\=2^0\cdot3^2=1\cdot9=\boxed{9}\\\\Used:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}\\\\a^{-n}=\dfrac{1}{a^n}

4 0
4 years ago
Read 2 more answers
I'm in 8th grade I need help with this question plz help me. Screen Shot 2021-01-29 at 1.10.42 PM
shtirl [24]
Yeah sure, but i need to see the picture to get your answer
3 0
3 years ago
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Pls help me asap!!!!
RUDIKE [14]

Answer:b

Step-by-step explanation:y=2x-3

5 0
3 years ago
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