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4 years ago

-Please help I need it super bad I don't want to fail :(

Mathematics

1 answer:

bogdanovich [222]4 years ago

4 0

Answer:

;-;

Step-by-step explanation:

1) 153.86cm²

2) 28.26cm²

3) 65.94cm²

4) 63.585cm²

5) 8167.14ft²

6) 78.5m²

7) 314in²

8) 490.625cm²

9) 1384.74ft²

10) 50.24m²

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If log 2=a and log 3=b express log 12 in terms of a and b.

Arisa [49]

Answer:

2a +b

Step-by-step explanation:

The rule for logarithms is ...

log(xy) = log(x) +log(y)

Applying this to the given problem, we have ...

log(12) = log(2×2×3)

= log(2) +log(2) +log(3)

= a + a + b

= 2a +b

7 0

3 years ago

Find the coordinates of the midpoint of the segment whose endpoints are h(6,4) and k(2,8)

ozzi

Answer:

$(4,6)$

Step-by-step explanation:

we know that

The formula to calculate the coordinates of the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have that

The coordinates of hk

$h(6,4), k(2,8)$

substitute in the formula to calculate the midpoint

$M(\frac{6+2}{2},\frac{4+8}{2})$

$M(\frac{8}{2},\frac{12}{2})$

$M(4,6)$

7 0

3 years ago

Read 2 more answers

What is the true solution to 2 In 4x= 2 In 8?

vladimir2022 [97]

Answer:

Step-by-step explanation:

$ln4x = 2 ln8 \div 2 \\ ln4x = ln4 \\ x = 1$

Hope it helps you...☺

6 0

4 years ago

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CAN U PLEASE HELP AS FAST AS POSSIBLE

kondaur [170]

Answer:

5/14 is the answer I believe

5 0

3 years ago

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Convert the rational expression to a radical...don't mind the answers I put I just need someone to show me how they do it step b

bazaltina [42]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-----------------------------\\\\
thus\implies x^{\frac{2}{5}}\implies \sqrt[5]{x^2}
\\\\\\
and\implies (4ab)^{\frac{3}{5}}\implies \sqrt[5]{(4ab)^3}\implies \sqrt[5]{4^3a^3b^3}
\\\\
-----------------------------\\\\

now\\\\ 4\to 2^2\qquad and\qquad 4^3\to (2^2)^3\to 2^{2\cdot 3}\to 2^6\to 2^{5+1}\to 2^52^1\\\\
-----------------------------\\\\

$

$\bf \sqrt[5]{4^3a^3b^3}\implies \sqrt[5]{2^52^1a^3b^3}\implies 2\sqrt[5]{2a^3b^3}$

8 0

4 years ago