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kolbaska11 [484]
1 year ago
12

The internal height of a rectangular box is 10.5cm.The thickness of the bottom is 3/5cm and the thickness of the top is 1cm.What

is the eternal height of the box?​
Mathematics
1 answer:
omeli [17]1 year ago
7 0

The addition is one of the four fundamental mathematical operations, the others being subtraction, multiplication, and division. The external height of the box is 12.1 cm.

<h3>What is Addition?</h3>

The addition is one of the four fundamental mathematical operations, the others being subtraction, multiplication, and division. When two whole numbers are added together, the total quantity or sum of those values is obtained.


Given that the internal height of a rectangular box is 10.5cm. The thickness of the bottom is 3/5cm and the thickness of the top is 1cm. Therefore, the external height of the rectangular box is,

Height of rectangular box

= Thickness of bottom + Internal height of the box + Thickness of the top

= 3/5 cm + 10.5 cm + 1 cm

= 0.6cm + 10.5cm + 1cm

= 12.1 cm

Hence, the external height of the box is 12.1 cm.

Learn more about Addition here:

brainly.com/question/14092461

#SPJ1

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iren2701 [21]

Answer:

The distance between points A and B is 13

Step-by-step explanation:

We need to find distance between points A and B

Looking at the graph,

Point A : (2,6) and Point B: (-3,-6)

We need to find the distance between these points.

The formula used is: Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

We have Points A : (2,6) and  B: (-3,-6)

So, x_1=2, y_1=6, x_2=-3, y_2=-6

Putting values in formula and finding distance

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\Distance=\sqrt{(-3-2)^2+(-6-6)^2} \\Distance=\sqrt{(-5)^2+(-12)^2} \\Distance=\sqrt{25+144} \\Distance =\sqrt{169}\\Distance = 13

So, the distance between points A and B is 13

6 0
3 years ago
Solve for x In the triangle
Goryan [66]
\boxed {\boxed { \sin(\theta) = \dfrac{\text{opp}}{\text{hyp}} }}

\sin(38 \textdegree) =  \dfrac{x}{11}

x = 11 \times \sin(38 \textdegree)

x = 6.8 \text { units}
8 0
3 years ago
Please answer now I will give the crown thingy
Wewaii [24]

Answer:

three times

Step-by-step explanation:

8 0
2 years ago
Arrange the pairs of points in increasing order of the slopes of the lines joining them. (15, 30) and (20, 40)
gavmur [86]

Answer: m1 = 0.5

M2= 0.375

M3 = 2.25

M4 = 3.0

M5 = 13.5

M6 = 0.285

M7 = 7.0

Step-by-step explanation:

(20,40)-(15,30)=(5,10), m1=5/10=0.5

(18,48)-(12,32)=(6,16), m2=3/8=0.375

(72,32)-(27,12)=(45,20), m3=9/4=2.25

(60,20)-(45,15)=(15,5), m4=3.0

(243,18)-(27,2)=(216,16), m5=27/2=13.5

(24,84)-(18,63)=(6,21), m6=2/7=0.285...

(84,12)-(63,9)=(21,3), m7=7.0

4 0
3 years ago
Find the area of quadrilateral ABCD
andreev551 [17]

Answer:

<em>A ≈ 28.5</em>

Step-by-step explanation:

a, b, c

P = a + b + c

Semiperimeter s = \frac{a+b+c}{2}

A = \sqrt{s(s-a)(s-b)(s-c)}

~~~~~~~~~~~~~~~

P_{ABC} = 4.3 + 2.89 + 6.81 = 14

s = 14 ÷ 2 = 7

A_{ABC} = \sqrt{7(7-4.3)(7-2.89)(7-6.81)} = √14.75901 ≈ 3.84

P_{BCD} = 8.59 + 7.58 + 6.81 = 22.98

s = 22.98 ÷ 2 = 11.49

A_{BCD} = \sqrt{11.49(11.49-8.59)(11.49-7.58)(11.49-6.81)} = √609.7343148 ≈ 24.6928

A_{ABCD} = 3.84 + 24.6928 ≈ <em>28.5</em>

3 0
2 years ago
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