Answer:
Step-by-step explanation:
We are given;
- The equation of a line 6x-2y=4+6y
- A point (8, -16)
We are required to determine the equation of a line parallel to the given line and passing through the given point.
- One way we can determine the equation of a line is when we are given its slope and a point where it is passing through,
First we get the slope of the line from the equation given;
- We write the equation in the form y = mx + c, where m is the slope
That is;
6x-2y=4+6y
6y + 2y = 6x-4
8y = 6x -4
We get, y = 3/4 x - 4
Therefore, the slope, m₁ = 3/4
But; for parallel lines m₁=m₂
Therefore, the slope of the line in question, m₂ = 3/4
To get the equation of the line;
We take a point (x, y) and the point (8, -16) together with the slope;
That is;
Thus, the equation required is
Okay, to answer this question,
<span>Perpendicular lines have slopes that are inverse of one another and with opposite signs so,
If a line has a slope of m= -2 than a perpendicular line will have slope m=1/2
If a line has a slope of m= -3/4 than a perpendicular line will have slope m=4/3
If a line has a slope of m= 6 than a perpendicular line will have slope m=-1/6
So, just find the slope of your line, using it, get the slope of the line that will be perpendicular and then just get the equation for a line that has that slope and passes through point (-2,3) using:
y - y1 = m(x - x1)
I hope I helped you with my answer</span>
15÷8=1.875
I would round up to $1.88 /cookie.
Answer:
a. 7
Explanation:
A coefficient is the number in front of the variable that is to be multiplied by said variable. Simply identify the coefficient in the term provided to solve the problem.
