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scoray [572]
3 years ago
14

PLEASE HELP ME SOLVE WILL MARK AS BRAINLIEST IF ANSWERED CORRECTLY AMND SERIOUSLY

Mathematics
2 answers:
noname [10]3 years ago
6 0
We can simplify this equation and find the value of k.

k ÷ 2 + 1 - 1k = -2k
k ÷ 2 + 1 = -k
k + 1 = -2k
1 = -3k
k = -1/3
postnew [5]3 years ago
5 0
Answer:   k = "- \frac{2}{3}"  ; or, write as:   " -0.667 " .

_________________________________________________________
Given:

(k/2)  + 1  -  1k  = -2k ;  
_________________________________________________________

Add "1k" to each side of the equation:

(k/2)  + 1  -  1k  + 1k  =  -2k + 1k  ;

to get:


(k/2)  + 1  =  -1k ; 

Multiply the ENTIRE EQUATION (both sides) by "2" ;  
               to eliminate the "fraction" ;

2 * [ (k/2) + 1 = -1k ] ;


to get:

k + 2 =  -2k  ;

Subtract "k" from each side of the equation;

k + 2 - k = -2k - k ;

to get:

2  =  -3k ;

↔  

-3k = 2 ;

Divide each side of the equation by "-3" ; to isolate "k" on one side of the equation ; &  to solve for "k" ;

-3k / 3  = 2/-3 ;

to get:

k = - \frac{2}{3}  ; or, write as:   " -0.667 "
______________________________________________ 
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Alex777 [14]

Answer:

please last option

using 45 degree as reference angle

using tan relation

Tan45=perpendicular /base

1 = x\6

x = 6

now using right angled triangle relation

H²=p²+b²

then h²= 6²+6²

H = √36+36

H =6√2

therefore y=6√2

5 0
3 years ago
1)) Select the missing property.
irinina [24]

Answer:

associative property

Step-by-step explanation:

5 0
4 years ago
Consider the sequence {an} = {nrn}. Decide whether {an} converges for each value of r.
Rudiy27

Answer:

a). converges

b). diverges

c). converges

Step-by-step explanation:

{ $ a_n $ } = { $ nr^n $ }

Using radio test,

L = $ \lim_{n \rightarrow \infty} |\frac{a_n + 1}{a_n}| $

   = $ \lim_{n \rightarrow \infty} |\frac{(n+1)r^{n+1}}{nr^n}| $

   = $ \lim_{n \rightarrow \infty} |(1+\frac{1}{n})^r| $

   = $ \lim_{n \rightarrow \infty} |r| $

   = |r|

Therefore, $a_n$ converges in |r| < 1

a). r = 1/5

    $\{ a_n \}=  \{\frac{1}{5}, n \}$

This sequence is monotonically decreasing and bounded.

0 < $ a_n $ < 1

Hence, { $ a_n $ } converges.

b). r = 1

    { $ a_n $ } = { n }

This sequence is monotonically increasing sequence which is not bounded.

Hence, { $ a_n $ } diverges.

c). r = 1/6

$\{ a_n \}=  \{\frac{1}{6}, n \}$

This sequence is monotonically decreasing and bounded.

0 < $ a_n $ < 1

Hence, { $ a_n $ } converges.

For  |r| < 1, the $a_n$ converges.

3 0
3 years ago
Please help I have two questions left :)
grandymaker [24]

Answer:

120

Step-by-step explanation:

It us 120 because 100 us close to 120 the other numbers dont have anymore than more than 20

3 0
3 years ago
REALLY EASY PLZ SOLVE DONT IGNORE MY QUESTION LOL
Ivan

Answer:

bruh what grade is this tho

Step-by-step explanation:

4 0
3 years ago
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