PLEASE HELP ME SOLVE WILL MARK AS BRAINLIEST IF ANSWERED CORRECTLY AMND SERIOUSLY
2 answers:
Answer: k = "- 
" ; or, write as: " -0.667 " .
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Given:
(k/2) + 1 - 1k = -2k ;
_________________________________________________________
Add "1k" to each side of the equation:
(k/2) + 1 - 1k + 1k = -2k + 1k ;
to get:
(k/2) + 1 = -1k ;
Multiply the ENTIRE EQUATION (both sides) by "2" ;
to eliminate the "fraction" ;
2 * [ (k/2) + 1 = -1k ] ;
to get:
k + 2 = -2k ;
Subtract "k" from each side of the equation;
k + 2 - k = -2k - k ;
to get:
2 = -3k ;
↔
-3k = 2 ;
Divide each side of the equation by "-3" ; to isolate "k" on one side of the equation ; & to solve for "k" ;
-3k / 3 = 2/-3 ;
to get:
k = - ; or, write as: " -0.667 "
______________________________________________
_________________________________________________________
Given:
(k/2) + 1 - 1k = -2k ;
_________________________________________________________
Add "1k" to each side of the equation:
(k/2) + 1 - 1k + 1k = -2k + 1k ;
to get:
(k/2) + 1 = -1k ;
Multiply the ENTIRE EQUATION (both sides) by "2" ;
to eliminate the "fraction" ;
2 * [ (k/2) + 1 = -1k ] ;
to get:
k + 2 = -2k ;
Subtract "k" from each side of the equation;
k + 2 - k = -2k - k ;
to get:
2 = -3k ;
↔
-3k = 2 ;
Divide each side of the equation by "-3" ; to isolate "k" on one side of the equation ; & to solve for "k" ;
-3k / 3 = 2/-3 ;
to get:
k = -
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Answer:
256
Step-by-step explanation:
A calculator works well for this.
_____
None of the minus signs are subject to the exponents (because they are not in parentheses, as (-1)^5, for example. Since there are an even number of them in the product, their product is +1 and they can be ignored.
1 to any power is still 1, so the factors (1^n) can be ignored.
After you ignore all of the things that can be ignored, your problem simplifies to ...
(2^2)(2^-3)^-2
The rules of exponents applicable to this are ...
(a^b)^c = a^(b·c)
(a^b)(a^c) = a^(b+c)
Then your product simplifies to ...
(2^2)(2^((-3)(-2)) = (2^2)(2^6)
= 2^(2+6)
= 2^8 = 256
