Question

marlee spins a spinner and rolls 1-6 # cube. the spinner has 5 equal parts # 1-5 . what is the probability she will spin an even # and roll an odd #?

Answer 1

The events are independant (i.e. what she rolls on the cube has no impact on how the spinner works). The probability of two independant events is given by: 

$P_t = P_{cube} \times P_{spin}$

For the cube, 1/2 the numbers meet our requitment of being even, so:
$P_{cube} = \frac{Desired}{Total} = \frac{even}{total} = \frac{3}{6} =\frac{1}{2}$

For the spinner, there are 3 odds out of 5 (1, 3 & 5) so:
$P_{spin} =\frac{Desired}{Total} = \frac{odd}{total} = \frac{3}{5}$

and then:
$P_T = P_{cube} \times P_{spin}$
$P_T =\frac{1}{2} \times \frac{3}{5}$
$P_T =\frac{3}{10}$