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GrogVix [38]
3 years ago
15

Is perpendicular to ? Explain.

Mathematics
2 answers:
nika2105 [10]3 years ago
8 0

Answer:

????

Step-by-step explanation:

olga2289 [7]3 years ago
6 0
Two lines are perpendicular if and only if the product of their slopes is - 1.

So, you just need to find the slope of each line and find out the product of their slopes.

I will do one example for you.

L1: y = 3x + 5

L2: y = - 3x + 14

L3: y = -x/3 + 14

The slope of a line is the coefficient of the x.

So the slopes are:

L1: slope 3
L2: slope -3
L3: slope -1/3

So now multiply the slopes of each pair of lines:

L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular

L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular

L1 and L3: (3) *  (-1/3) = -1 => Yes, they are penpendicular.
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3 years ago
Help me please, this is really hard.
Snowcat [4.5K]

The points of new triangle is (3,-2), (6,-3) and (2,-5).

<u>Step-by-step explanation:</u>

The given points in the triangle A(-3,7), B(9,3) and C(-7,-5).

The scale factor is \frac{1}{4} and centered at point (5,-5).

The formula to dilate a point that is not centered on a origin is given by,

D(x,y)=(h+t(x-h),k+t(y-t)).

where (h,k) is the center point.

To find A',

D(-3,7)=(5+\frac{1}{4}(-3-5),-5+\frac{1}{4}(7+5)).

D(-3,7)=(5+\frac{1}{4}(-8),-5+\frac{1}{4}(12)).

D(-3,7)=(5-2, -5+3).

D(-3,7)=(3,-2).

To find B',

D(9,3)=(5+\frac{1}{4}(9-5),-5+\frac{1}{4}(3+5)).

D(9,3)=(5+\frac{1}{4}(4),-5+\frac{1}{4}(8)).

D(9,3) = (5+1,-5+2).

D(9.3)=(6,-3).

To find C',

D(-7,-5)=(5+\frac{1}{4}(-7-5),-5+\frac{1}{4}(-5+5)).

D(-7,-5)=(5+\frac{1}{4}(-12),-5+\frac{1}{4}(0)).

D(-7,-5)=(5-3,-5+0).

D(-7,-5)=(2,-5).

∴ The points of new triangle is (3,-2), (6,-3) and (2,-5).

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3 years ago
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IrinaVladis [17]

Answer:

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Step-by-step explanation:

y/3 - 4 = 2

y/3 = 6

y = 18

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