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2 years ago

15

Which system of equations does not have a real solution? y = x6 2 + 3x - 5 and x + y = -10 y = x6 2 + 3x - 5 and 4x + 5y = 20 y

= x 62+ 3x- 5 and x + y = -9

2 answers:

Yuri [45]2 years ago

5 0

I think it would be the first one but im not to positive

natta225 [31]2 years ago

5 0

Answer:

y = x ^2 + 3x - 5 and x + y = -10

Step-by-step explanation:

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Method 2:

$\begin{matrix}\dfrac{1}{4}\ \text{cup of corn}&-&\dfrac{1}{2}\ \text{cup of water}&|\text{multiply both sides by 2}\\\\\dfrac{1}{2}\ \text{cup of corn}&-&1\ \text{cup of water}&|\text{multiply both sides by 2}\\\\1\ \text{cup of corn}&-&2\ \text{cup of water}&|\end{matrix}$

$\begin{matrix}\left(\dfrac{1}{2}+1\right)\ \text{cups of corn}&-&(1+2)\ \text{cups of water}\\\\1\dfrac{1}{2}\ \text{cups of corn}&-&3\ \text{cups of water}\end{matrix}$

<h3>Answer: Henry will need 3 cups of water.</h3>

5 0

3 years ago

Read 2 more answers