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Monica [59]
3 years ago
7

I need help with the rest of those problems? the ones that are blank.

Mathematics
1 answer:
maks197457 [2]3 years ago
3 0
Problem #11:

Twice a number (n) decreased by 5 is at least 11.
          2n                    -                   5   is = to or greater than 11.

          2n - 5 is = to 11 comes out as 2n = 11 + 5, or 2n = 16, or n = 8.

If n = 8 or is greater than 8,  2n=5 will be at least 11.


Please, start work on the problems you haven't yet done.  I'd be happy to comment on your own work and help you bring the solution to conclusion.

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VikaD [51]
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3 years ago
a traveler has 7 pieces of luggage . how many ways can the traveler select 3 pieces of luggage for a trip
7nadin3 [17]
Well, you could assign a letter to each piece of luggage like so...

A, B, C, D, E, F, G

What you could then do is set it against a table (a configuration table to be precise) with the same letters, and repeat the process again. If the order of these pieces of luggage also has to be taken into account, you'll end up with more configurations.

My answer and workings are below...

35 arrangements without order taken into consideration, because there are 35 ways in which to select 3 objects from the 7 objects.

210 arrangements (35 x 6) when order is taken into consideration.

*There are 6 ways to configure 3 letters.

Alternative way to solve the problem...

Produce Pascal's triangle. If you want to know how many ways in which you can choose 3 objects from 7, select (7 3) in Pascal's triangle which is equal to 35. Now, there are 6 ways in which to configure 3 objects if you are concerned about order.

7 0
3 years ago
I need help with this
Fudgin [204]
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5 0
3 years ago
Help please I’m not sure if this is right
Schach [20]

Answer:

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6 0
3 years ago
6. What are the extremes of the following proportion?<br> 3/5 = 12%
GuDViN [60]

3/5 = 12/100

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solution false

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3 years ago
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