I need help with the rest of those problems? the ones that are blank.
1 answer:
Problem #11:
Twice a number (n) decreased by 5 is at least 11.
2n - 5 is = to or greater than 11.
2n - 5 is = to 11 comes out as 2n = 11 + 5, or 2n = 16, or n = 8.
If n = 8 or is greater than 8, 2n=5 will be at least 11.
Please, start work on the problems you haven't yet done. I'd be happy to comment on your own work and help you bring the solution to conclusion.
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1. distribute a 1 to the 12 and 8a
2. you'll get 15+ 12 +8a
3. add the like terms(15 and 12)
4. your final answer will be 27+8a
