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AVprozaik [17]
3 years ago
9

In triangle ABC, the measure of angle B is 44 degrees more than three times the measure of angle A. The measure of angle C is 61

degrees more than the measure of angle A. Find the measure of each angle

Mathematics
1 answer:
lianna [129]3 years ago
7 0

Answer:

m∠A = 15°; m∠B = 89°; m∠C = 76°

Step-by-step explanation:

The sum of the three interior angles of a triangle is 180°.

             Let x = m∠A

Then 3x + 44 = m∠B

    and x + 61 = m∠C

x + 3x + 44 + x + 61 = 180

                  5x + 105 = 180

                            5x =   75

                               x =   15

m∠A =                                       15°

m∠B = 3(15) + 44 = 45 + 44 =   89°

m∠C =                       15 + 61 = <u>  76°</u>

                                      Sum = 180°

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Write an equation of a polynomial with the given characteristics: a quadratic function has x -intercepts of -3 and 1, and a y-in
fredd [130]

Answer:

f(x) = -3(x+3)(x-1)

Step-by-step explanation:

x = -3 & 1; f(x) = 9

f(x) = a(x-r1)(x-r2)

f(0) = a(x-r1)(x-r2) = 9; 9 = a(0-(-3))(0-1)

9 = a(3)(-1); 9 = a(-3)

a = -3

f(x) = -3(x+3)(x-1)

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3 years ago
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In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s
Oksi-84 [34.3K]

Answer:

a) \mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

b) From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

c) P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

P(Z\geq2.070)=1-P(Z

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

\mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

Part b

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

Part c

For this case we want this probability:

P(\bar X \geq 285)

And we can use the z score defined as:

z=\frac{\bar x -\mu}{\sigma_{\bar x}}

And using this we got:

P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

And using a calculator, excel or the normal standard table we have that:

P(Z\geq2.070)=1-P(Z

8 0
3 years ago
A venue plans to host trucking events regularly throughout the year. The expected revenue from each event is $100,000. The cost
iris [78.8K]

Answer:

The venue has to host 47 events throughout the year

Step-by-step explanation:

Profit:

Profit is revenue subtracted by costs.

Per event:

$100,000 revenue

$50,000 costs

$100,000 - $50,000 = $50,000 profit.

If the venue wants to make a total profit margin of $2,350,000, how many events does the venue have to host throughout the year?

1 event - $50,000 profit.

x events - $2,350,000 profit.

50000x = 2350000

x = \frac{2350000}{50000}

x = 47

The venue has to host 47 events throughout the year

6 0
3 years ago
Plz help me thanks very nuch whoever helped me​
photoshop1234 [79]

Answer:

(1) 56 miles/hour

Step-by-step explanation:

We need to find the average rate of change from t = 2 to t = 9.

At t = 2 hours, d = 106 miles.

At t = 9 hours, d = 498 miles.

The average rate of change in function f(x) from x = a to x = b is

[f(b) - f(a)]/(b - a)

average rate of change from t = 2 to t = 9 =

(498 - 106)/(9 - 2) = 392/7 = 56

Answer: (1) 56 miles/hour

7 0
3 years ago
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