Secxcotx=cscx Verify this with steps please :))))

Mathematics

1 answer:

Jlenok [28]2 years ago

4 0

Secxcotx=cscx
1/cos * cos/sin =cscx
cos/sincos=csc
1/sin=csc

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2 years ago

What is 1/6d+2/3 = 1/4(d-2)

GenaCL600 [577]

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First, simplify $\frac{1}{6} d$ to $\frac{d}{6}$ / Your problem should look like: $\frac{d}{6}$ + $\frac{2}{3}$ = $\frac{1}{4}$ (d - 2)
Second, simplify $\frac{1}{4} (d - 2)$ to $\frac{d-2}{4}$ / Your problem should look like: $\frac{d}{6}$ + $\frac{2}{3}$ = $\frac{d-2}{4}$
Third, multiply both sides by 12 (the LCM of 6,4) / Your problem should look like: 2d + 8 = 3(d - 2)
Fourth, expand. / Your problem should look like: 2d + 8 = 3d - 6
Fifth, subtract 2d from both sides. / Your problem should look like: 8 = 3d - 6 - 2d
Sixth, simplify 3d - 6 - 2d to d - 6 / Your problem should look like: 8 = d - 6
Seventh,add 6 to both sides. / Your problem should look like: 8 + 6 = d
Eighth, simplify 8 + 6 to 14 / Your problem should look like:14 = d
Ninth, switch sides. / Your problem should look like: d = 14

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2 years ago

A parallelogram has sides 10m and 12m and an angle of 45°. Find the distance between the 12m-sides.

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