The ball takes approximately a time of 2.041 seconds to reach its maximum height.
<h3>What time does the ball take to reach maximum height?</h3>
The height of the ball as a function of time is modelled by a <em>quadratic</em> equation, the required information can be found by transforming the expression into <em>vertex</em> form:
h = - 4.9 · t² + 20 · t + 12
h = - 4.9 · (t² - 4.082 · t - 2.449)
h + (- 4.9) · (6.615) = - 4.9 · (t² - 4.082 · t + 4.166)
h - 32.414 = - 4.9 · (t - 2.041)²
The ball takes approximately a time of 2.041 seconds to reach its maximum height.
To learn more on quadratic equations: brainly.com/question/1863222
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Answer:
11/2n+-1/2p-2
Step-by-step explanation:
simplification
Answer: 95.55%
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Work Shown:
A = event that copier A breaks down
B = event that copier B breaks down
P(A) = probability that copier A breaks down
P(A) = 2% = 0.02
P(B) = probability that copier B breaks down
P(B) = 2.5% = 0.025
P(neither break down) = (1-P(A))*(1-P(B))
P(neither break down) = (1-0.02)*(1-0.025)
P(neither break down) = 0.9555
P(neither break down) = 95.55%
17.6 because you do the working out backwards :)