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ki77a [65]
3 years ago
6

2. A random sample of adults are asked about their preferences for a first dinner date with

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
6 0

All the attatchments include the directions below:

Prepare a two-way table as shown below.

Enter the number 50 in the two-way table

Prepare a column total and enter 68 for the total number of people who split the check.

The total number of people who do not eat desert are 56, and the total number of people who took the survey are 122. Enter both values.

The remaining values can be found out as shown below.

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black pencils cost 75 naira each and colour pencils cost 105 naira each if 24 mixed pencils cost 2010 naira how many of them wer
KonstantinChe [14]

Answer:

number of black pencils is 17

7 0
3 years ago
A church steeple is 30 feet tall with square cross sections. The square at the base has side 3 feet, the square at the top has s
JulijaS [17]

Answer:

Volume= 540 ft^3

Step-by-step explanation:

Since volume= length times Width times height, you do 3 times 6 times 30= 540 ft^cubed.

3 0
3 years ago
I need to know how to do it in Distributive Property.
kotykmax [81]
A(b-c)=ab-ac

(1/7)(1/3h-1/2)=(1/7)(1/3h)-(1/7)(1/2)=1/21h-1/14

now we gots
6 and 1/7+1/21h-1/14
rearange
6 and 1/7-1/14+1/21h
make common denom which is 14
6 and 2/14-1/14+1/21h
6 and 1/14+1/21h

6 0
3 years ago
PLEASE HELP!!!!!!!dgbdgdbhdndcn
bogdanovich [222]
Problem 1)

AC is only perpendicular to EF if angle ADE is 90 degrees

(angle ADE) + (angle DAE) + (angle AED) = 180
(angle ADE) + (44) + (48) = 180
(angle ADE) + 92 = 180
(angle ADE) + 92 - 92 = 180 - 92
angle ADE  = 88

Since angle ADE is actually 88 degrees, we do NOT have a right angle so we do NOT have a right triangle

Triangle AED is acute (all 3 angles are less than 90 degrees)

So because angle ADE is NOT 90 degrees, this means AC is NOT perpendicular to EF

-------------------------------------------------------------

Problem 2)

a) The center is (2,-3) 

The center is (h,k) and we can see that h = 2 and k = -3. It might help to write (x-2)^2+(y+3)^2 = 9 into (x-2)^2+(y-(-3))^2 = 3^3 then compare it to (x-h)^2 + (y-k)^2 = r^2

---------------------

b) The radius is 3 and the diameter is 6

From part a), we have (x-2)^2+(y-(-3))^2 = 3^3 matching (x-h)^2 + (y-k)^2 = r^2

where
h = 2
k = -3
r = 3

so, radius = r = 3
diameter = d = 2*r = 2*3 = 6

---------------------

c) The graph is shown in the image attachment. It is a circle with center point C = (2,-3) and radius r = 3.

Some points on the circle are

A = (2, 0)
B = (5, -3)
D = (2, -6)
E = (-1, -3)

Note how the distance from the center C to some point on the circle, say point B, is 3 units. In other words segment BC = 3.

6 0
3 years ago
The width of a soccer goal is 7 m. how wide is the goal in centimeters ?
Ratling [72]
We know, 1 m = 100 cm
Multiply both sides by 7, 
7 m = 100 * 7 = 700 cm

In short, Your Answer would be 700 cm

Hope this helps!
4 0
3 years ago
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