All categories

3 years ago

When constructing an inscribed square, what step comes after both diameters of the circle have been created?

Mathematics

2 answers:

sweet [91]3 years ago

6 0

Answer:

Connect the intersections of the diameters and the circle with a segment.

melisa1 [442]3 years ago

3 0

Answer: D connect the midpoint of the radius to the end point

Step-by-step explanation: you always have to create the mid point once the diameter was made

You might be interested in

I will mark as brainliest:)

labwork [276]

Hii I believe your option would be D. I hope it helps :)

8 0

3 years ago

Read 2 more answers

Differentiate x^2 e^x logx

zimovet [89]

Product rule:

$\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)$

$=\dfrac{\mathrm d(x^2)}{\mathrm dx}e^x\log x+x^2\dfrac{\mathrm d(e^x)}{\mathrm dx}\log x+x^2e^x\dfrac{\mathrm d(\log x)}{\mathrm dx}$

Power rule:

$\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x$

The exponential function is its own derivative:

$\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x$

Assuming the base of $\log x$ is $e$ , its derivative is

$\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x$

But if you mean a logarithm of arbitrary base $b$ , we have

$y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{e^{-y\ln b}}{\ln b}=\dfrac1{b^y\ln b}$

$\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}$

So we end up with

$2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x$

$=xe^x(2\log x+x\log x+1)$

8 0

3 years ago

Olce Question What type of notation uses these brackets {}? A. Interval B. Set

Sergio [31]

Answer:

Interval?

Step-by-step explanation:

5 0

3 years ago

5(x−6+3x)2−6 where x=2 .

hram777 [196]

Answer:

Step-by-step explanation:

5(x−6+3x)2−6

10(4x-6)-6

40x-60-6

40x-66

x=2

40*2-66

80-66

4 0

3 years ago

Read 2 more answers

The fraction 7/9 produces a repeating decimal 0.7 A. true B. false

Elis [28]

Answer:

false for 0.7 it would have to be 7/10

Step-by-step explanation:

7 0

3 years ago