Answer:
the graph ^
Step-by-step explanation:
this is fun for no reason
Let's look at the first equation.
3y = 5x - 1
y = 5/3 y - 1/3
This line has slope 5/3. A line perpendicular to it has slope -3/5.
The second line is y = -3/5 x + 9.
Its slope is indeed -3/5, so the second line is perpendicular to the first one.
There is an infinite number of lines perpendicular to any given line. You concluded correctly that the two lines in this problem are perpendicular based on the fact that their slopes are negative reciprocals. The second line, y = -3/5 x + 9, is only one line that is perpendicular to the first line. There is an infinite number of lines perpendicular to the first line. All the perpendicular lines have the slope -3/5 and different y-intercepts. The +9 here is just the y-intercept of this specific perpendicular line. Since there is an infinite number of y-intercepts, there is an infinite number of perpendiculars.
Take the problem and solve it about the information about the type of icecream
Answer:
D) 1/4
Step-by-step explanation:
To solve this, first lets figure out what this variable is. We know we must multiply by t. Well, looking at it, we know that t is one. So lets plug that in.
2*1/2^3(1)
Now we need to figure out what the exponent is that 2 will be raised to. To find that, find out what 3 times one is.
2*1/2^3
Now we need to solve the exponent.
2*1/8
Remember, 2 cubed is eight.
Now we need to find out what 2*1/8 is. To solve this more easily, I am going to turn two into a fraction. This will give us 2/1*1/8. Now we cross multiply, multiplying the numerators by the numerators, and the denominators by the denominators. Remember, the numerator is the top number, and the denominator is the bottom number.
If we do that, we get:
2/8
If we simplify it, we get 1/4. So the asnwer is D) 1/4
First, find any zero of the polynomial. Since you didn't ask for work, I'll assume it's okay if I use my calculator. Your given polynomial has only one real root which is x=-4.
Now we use the rule that x-a divides the polynomial where a is a zero of said polynomial.
So x+4 divides 2x^3+2x^2-19x+20.
<span>(2x^3+2x^2-19x+20) / (x+4 equals 2x^2-6x+5).
If we factor out a two, we can use the quadratic formula.
2(x^2-3x+2.5) so we have x = (-(-3)+/-(9-4*1*2.5)^(1/2))/2*1)=(3+i)... or (3-i)/2 Where i is the square root of negative one. final answer:
2x^3+2x^2-19x+20=0
then x=-4, (3+i)/2, or (3-i)/2
</span>we have two imaginary number.
I hope it helped you
