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solmaris [256]
3 years ago
10

Edward deposited $6,000 into a savings account 4 years ago. The simple interest rate is 3%. How much money did Edward earn in in

terest?
Mathematics
1 answer:
GaryK [48]3 years ago
6 0
Hello IdontKnowHowToMath,

first, converting R percent to r a decimal
r = R/100 = 3%/100 = 0.03 per year.

Solving our equation:
A = 6000(1 + (0.03 × 4)) = 6720
A = $6,720.00

The total amount accrued, principal plus interest, from simple interest on a principal of $6,000.00 at a rate of 3% per year for 4 years is $6,720.00.
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Mr. Moran chose 10 different test scores out of 50, and they are shown below. For the following set of data, find the mean test
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Answer:

39.5

Step-by-step explanation:

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3 years ago
What's the answer of 75% of what number is 60
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75% of 60
OF MEANS times
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45 
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Determine the period of each function. <br><br> Show Work plzzz
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2 years ago
A piece of cardboard is 15 inches by 30 inches. A square is to be cut from each corner and the sides folded up to make an open-t
solmaris [256]

Answer:

Maximum volume = 649.519 cubic inches

Step-by-step explanation:

A rectangular piece of cardboard of side 15 inches by 30 inches is cut in such that a square is cut from each corner. Let x be the side of this square cut. When it was folded to make the box the height of box becomes x, length becomes (30-2x) and the width becomes (15-2x).

Volume is given by  

V = V = Length\times Width\times Height\\V = (30 - 2x)(15-2x)x= 4x^3-90x^2+450x\\So,\\V(x) = 4x^3-90x^2+450x

First, we differentiate V(x) with respect to x, to get,

\frac{d(V(x))}{dx} = \frac{d(4x^3-12x^2+9x)}{dx} = 12x^2 - 180x +450

Equating the first derivative to zero, we get,

\frac{d(V(x))}{dx} = 0\\\\12x^2 - 180x +450 = 0

Solving, with the help of quadratic formula, we get,

x = \displaystyle\frac{5(3+\sqrt{3})}{2}, \frac{5(3-\sqrt{3})}{2},

Again differentiation V(x), with respect to x, we get,

\frac{d^2(V(x))}{dx^2} = 24x - 180

At x =

\displaystyle\frac{5(3-\sqrt{3})}{2},

\frac{d^2(V(x))}{dx^2} < 0

Thus, by double derivative test, the maxima occurs at

x = \displaystyle\frac{5(3-\sqrt{3})}{2} for V(x).

Thus, largest volume the box can have occurs when x = \displaystyle\frac{5(3-\sqrt{3})}{2}}.

Maximum volume =

V(\displaystyle\frac{5(3-\sqrt{3})}{2}) = (30 - 2x)(15-2x)x = 649.5191\text{ cubic inches}

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3 years ago
Graph Equation 1: 6x - 3y = 3 Equation 2: 4x - 2y = 8 *
tatiyna

6x - 3y = 3 will be graph 1

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