From 1st condition:
3^(x+1)=81
Take log on both sides,
➡ log [3^(x+1)]=log81
Use the property: log(x^a)=a logx
➡ (x+1) log 3=log(3⁴)
➡ (x+1) log 3=4×log 3
➡ (x+1)=4 (log 3 /log 3)
➡ x+1=4
➡ x=3➡↪➡↪ ANS
From 2nd condition, (Same process are repeated)
81^(x-y)=3
➡ 3^4(x-y)=3
➡ log [3^4(3-y)]=log 3
➡ 4(3-y) log 3=log 3
➡ (3-y)=(log 3)/(4log 3)
➡ 3-y=(1/4)
➡ y=11/4 ➡↪➡↪ ANS
Answer:
So like I shouldn't represent with a letter? I should use 2?
take the absolute value of the coefficient (2)
then the lower bound is the negative of that (-2)
so the range is [-2,2]
Answer:
x = -9/5
y = 16/5
Step-by-step explanation:
-3x-2y=-1 first you need to multiply the numerator by 3 so when adding
4x+6y=12 the y's cancel and you get a single variable
3(-3x-2y=-1) —> -9x - 6y = -3 then you add the like terms
4x+6y=12 —> 4x + 6y = 12
(-9x+4x) + (6y - 6y) = (-3 + 12)
-5x = 9 then you divide by -5
x = -9/5
then you plug this in to either equation
4(-9/5) + 6y = 12
-36/5 + 6y = 12 then you add 36/5 to both sides
6y = 96/5 then you divide by 6
y = 16/5
Answer: 1,2,4
Step-by-step explanation: hope it helps thx for the points :)
