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Leni [432]
3 years ago
13

7x+49=2x+94 solve for x

Mathematics
2 answers:
Illusion [34]3 years ago
4 0

Answer: x=9

Step-by-step explanation:

7x=2x+45

5x=45

x=9

krok68 [10]3 years ago
4 0

Answer:

x=9

Hope this helps :)

Step-by-step explanation:

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Can an expert help me with this. thanx
pogonyaev

141 perimeter

I cannot help with the area tho.

7 0
3 years ago
Let M be the set of all nxn matrices. Define a relation on won M by A B there exists an invertible matrix P such that A = P BP S
Sophie [7]

Answer:

Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that A=J^{-1}AJ. Thus, A↔A.

<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that A=P^{-1}BP. In this equality we can perform a right multiplication by P^{-1} and obtain AP^{-1} =P^{-1}B. Then, in the obtained equality we perform a left multiplication by P and get PAP^{-1} =B. If we write Q=P^{-1} and Q^{-1} = P we have B = Q^{-1}AQ. Thus, B↔A.

<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have A=P^{-1}BP and from B↔C we have B=Q^{-1}CQ. Now, if we substitute the last equality into the first one we get

A=P^{-1}Q^{-1}CQP = (P^{-1}Q^{-1})C(QP).

Recall that if P and Q are invertible, then QP is invertible and (QP)^{-1}=P^{-1}Q^{-1}. So, if we denote R=QP we obtained that

A=R^{-1}CR. Hence, A↔C.

Therefore, the relation is an <em>equivalence relation</em>.

4 0
4 years ago
You start driving north for 7 miles, turn right, and drive east for another 24 miles. At the end of driving, what is your straig
horsena [70]

Answer:

AC = 25\ miles

Step-by-step explanation:

Given:

Distance for north side = 7 miles.

Distance for east side = 24 miles.

We need to find the displacement.

Solution:

Figure shows Point A is starting point and AB = 7 miles is North side distance and BC = 24 miles is east side distance and AC is shown as displacement.

Using Pythagoras theorem to find displacement (AC).

(AC)^{2}=(AB)^{2}+(BC)^{2}

Substitute AB = 7 and BC = 24 in above equation.

(AC)^{2}=(7)^{2}+(24)^{2}

(AC)^{2}=49+576

(AC)^{2}=625

AC = \sqrt{625}

AC = 25\ miles

Therefore, displacement of the car AC = 25\ miles

3 0
3 years ago
Someone know how to solve this one
slavikrds [6]

Answer:

diagonals bisect each other equally in rectangle

then use the concept of vertically opposite angles

7 0
3 years ago
Read 2 more answers
A book advertised as 20% off. If it cost 70$ how much was it originally
Galina-37 [17]

Answer:

The answer is $84

Step-by-step explanation:

hope this helps

$70×0.2=14

$70+$14=$84

5 0
3 years ago
Read 2 more answers
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