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Amiraneli [1.4K]

3 years ago

5

A triangle has a base of 17 inches and a area of 127.5 square inches. What is the height of the triangle?

1 answer:

zmey [24]3 years ago

8 0

We know that area=0.5*base*height.

Thus, the equation would look like:
127.5=0.5*base*height

That means, 255 = base*height.
We know base is 17
Then, we divide 255 by 17. That gets us the height.
The height equals 15.

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Write a formula for the area A of a parallelogram.

OleMash [197]

To find the area of a parallelogram, multiply the base by the height. the formula is: A= Base times height where B is the base, and H is the height, and * means multiply. the base and height of a parallelogram must be perpendicular

5 0

3 years ago

On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes

belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

$r = \frac{\Delta T_{X}}{\Delta T_{Y}}$

$r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}$

$r = 11\,\frac{^{\circ}X}{^{\circ}Y}$

The difference between current temperature in Y linear scale with respect to freezing point is:

$\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)$

$\Delta T_{Y} = 115\,^{\circ}Y$

The change in X linear scale is:

$\Delta T_{X} = r\cdot \Delta T_{Y}$

$\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)$

$\Delta T_{X} = 1265\,^{\circ}X$

Lastly, the current temperature on the X scale is:

$T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X$

$T_{X} = 1150\,^{\circ}X$

The current temperature on the X scale is 1150 °X.

5 0

3 years ago

One liter of paint covers 100 square feet. How many gallons of paint does it take to cover a room whose walls have an area of 80

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Its 3200 square feet so 32 gallons

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3 years ago

The length of a rectangular piece of land is 9 cm more than 3 times its width. The perimeter is 418 cm. Find its dimensions.

SashulF [63]

Let w represent the width of the rectangle in cm. Then its length in cm is (3w+9). The perimeter is the sum of two lengths and two widths, so is ...

... 418 = 2(w + (3w+9))

... 209 = 4w +9 . . . . . . divide by 2, collect terms

... 200 = 4w . . . . . . . . subtract 9

... 50 = w . . . . . . . . . . divide by 4

... length = 3w+9 = 3·50 +9 = 159

The dimensions of this piece of land are 159 cm by 50 cm.

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3 years ago

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Answer:

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Step-by-step explanation:

5 0

2 years ago

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