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1 answer:
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Answer:
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Step-by-step explanation:
Consider the provided information,
Let X is the number of defective bulbs.
Ten light bulbs are randomly selected.
The likelihood that a light bulb is defective is 5%.
Therefore sample size is = n = 10
Probability of a defective bulb = p = 0.05.
Therefore, q = 1 - p = 1 - 0.05 = 0.95
Mean of binomial random variable:
Therefore,
Variance of binomial random variable:
Therefore,
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Answer:
9/14
Step-by-step explanation:
The question is not clear enough. Here is a similar question as shown in the attachment
Given the expression
-3/2 ÷ -7/3
= -3/2 ×-3/7
= (-3*-3)/(2*7)
= 9/14
Hence the equivalent result expressed as a fraction is 9/14
