The wheel has diameter 60 cm = 0.60 m, and thus circumference π(0.60 m) ≈ 5.923 m.
In one complete revolution, a point on the edge of the wheel covers this distance, so that the wheel has an angular speed of
(13.2 m/s) * (1/5.923 rev/m) ≈ 2.229 rev/s
There are 60 seconds to each minute, and 60 minutes to each hour, so converting to rev/h gives
(2.229 rev/s) * (60 s/min) * (60 min/h) ≈ 8024 rev/h
If we expand bx to jx and kx we have:
5y^2-2y-7
5y^2-7y+5y-7 then factor...
y(5y-7)+1(5y-7)
(y+1)(5y-7)
So the other factor is:
(y+1)

=================================
the first term : 50
crosses point : (0, 50), (1, 90)
solve for y,


<h3>Thus D is correct option.</h3>
Graph:
I believe it should be 22½ or 22 books
You would need to divide 18 and ⅘
18 ÷ ⅘ = 22½
I hope this helps, even though I’m not totally sure :)