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snow_lady [41]
3 years ago
13

When eight times an unknown number is decreased by 208 the result is four times the unknown number.

Mathematics
1 answer:
Naddika [18.5K]3 years ago
6 0
I think

This is your typical algebra question where you are looking for an unknown value given some information. The information can be set up as:
8 - x = 4*(x +3)

Distribute the 4:
8 - x = 4x + 12

Rearrange to get variables on one side:
8 - 12 = 4x + x

Simplifiy:
-4 = 5x

Isolate the variable:
-4/5 = x
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The equation of a circle is given below. x^{2}+(y-2.25)^{2} = \dfrac{196}{169}x 2 +(y−2.25) 2 = 169 196 ​ x, squared, plus, left
Lostsunrise [7]
  • Center =(h,k) = (0,2.25)
  • Radius = r = \frac{14}{13}

<u>Step-by-step explanation:</u>

Here we have following equation : x^{2}+(y-2.25)^{2} = \dfrac{196}{169}

We need to find the center & radius of this circle . Let's find out:

We know that , Equation of a circle is given by :

⇒ (x-h)^2+(y-k)^2=r^2   ........(1)

Here , (h,k) are the co-ordinates of center & r is the radius of circle.Collectively called as a circle with radius r and center at (h,k) . Let's frame given equation in question :

⇒  x^{2}+(y-2.25)^{2} = \frac{196}{169}

⇒  (x-0)^{2}+(y-2.25)^{2} = (\frac{14}{13})^2

On comparing this equation with equation (1) we get :

  • Center =(h,k) = (0,2.25)
  • Radius = r = \frac{14}{13}
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Answer:

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To calculate the length of a spring with a 2 kg load, compare the displacement of a 1 kg load and adjust accordingly.

When a 1 kg load is suspended from the spring, the spring which is 6 cm stretches to 9 cm. This is 3 cm longer due to the weight. If you attach a weight which is twice as much then the displacement will be twice as much. Instead of stretching an additional 3 cm, it will stretch 2*3 = 6 cm. Add this to the length of the spring and it stretches in total 6 + 6 = 12 cm.

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