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3 years ago

When eight times an unknown number is decreased by 208 the result is four times the unknown number.

1 answer:

6 0

I think

This is your typical algebra question where you are looking for an unknown value given some information. The information can be set up as:
8 - x = 4*(x +3)

Distribute the 4:
8 - x = 4x + 12

Rearrange to get variables on one side:
8 - 12 = 4x + x

Simplifiy:
-4 = 5x

Isolate the variable:
-4/5 = x

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The equation of a circle is given below. x^{2}+(y-2.25)^{2} = \dfrac{196}{169}x 2 +(y−2.25) 2 = 169 196 x, squared, plus, left

Lostsunrise [7]

Center = $(h,k) = (0,2.25)$
Radius = $r = \frac{14}{13}$

<u>Step-by-step explanation:</u>

Here we have following equation : $x^{2}+(y-2.25)^{2} = \dfrac{196}{169}$

We need to find the center & radius of this circle . Let's find out:

We know that , Equation of a circle is given by :

⇒ $(x-h)^2+(y-k)^2=r^2$ ........(1)

Here , (h,k) are the co-ordinates of center & r is the radius of circle.Collectively called as a circle with radius r and center at (h,k) . Let's frame given equation in question :

⇒ $x^{2}+(y-2.25)^{2} = \frac{196}{169}$

⇒ $(x-0)^{2}+(y-2.25)^{2} = (\frac{14}{13})^2$

On comparing this equation with equation (1) we get :

Center = $(h,k) = (0,2.25)$
Radius = $r = \frac{14}{13}$

6 0

3 years ago

Read 2 more answers

What is the value of 1/4 to the power of 3

LenaWriter [7]

Answer:

1/64

Step-by-step explanation:

hope that helps

7 0

3 years ago

Isaac invested $77,000 in an account paying an interest rate of 4.6% compounded continuously. Assuming no deposits or withdrawal

zlopas [31]

Answer:

132,090.30

Step-by-step explanation:

r = R/100

r = 4.6%/100

r = 0.046 per year,

A = P(1 + r/n)nt

A = 77,000.00(1 + 0.046/1)(1)(12)

A = $ 132,090.30

3 0

2 years ago

Read 2 more answers

F(x) has domain (-4,-2, 0, 2, 4) and range

CaHeK987 [17]

Answer:

1/2

Step-by-step explanation:

I just did the problem on edgenuity.

8 0

2 years ago

A 6 cm long spring extends to 9 cm when a 1 kg load is suspended from it. What would be its length if a 2 kg load were suspended

vampirchik [111]

Answer:

12 cm

Step-by-step explanation:

To calculate the length of a spring with a 2 kg load, compare the displacement of a 1 kg load and adjust accordingly.

When a 1 kg load is suspended from the spring, the spring which is 6 cm stretches to 9 cm. This is 3 cm longer due to the weight. If you attach a weight which is twice as much then the displacement will be twice as much. Instead of stretching an additional 3 cm, it will stretch 2*3 = 6 cm. Add this to the length of the spring and it stretches in total 6 + 6 = 12 cm.

4 0

3 years ago