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3 years ago

13. The red triangle shown is not

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

7 0

Answer:

I cannot answer see no red triangle to Base an answer on sorry is this calculus never took that course

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Hey please help me with this one. - Find the value fd a

valkas [14]

Answer: a = 15

Step-by-step explanation:

6a + 10 = 3a + 55

Subtract 10 from both sides

6a = 3a + 45

Subtract 3a from both sides

3a = 45

Divide each side by 3

a = 15

5 0

3 years ago

Given that ABCD is a rhombus, what is the value of x? (3x - 26)

ExtremeBDS [4]

<h2>The required "option B) $20.75\°$ " is correct.</h2>

Step-by-step explanation:

You can refer figure:

brainly.com/question/4386376

To find, the value of x = ?

We know that,

Consecutive angles are supplementary

The diagonals bisect the angles.

$2x\°+2(3x+7)\°=180\°$

Divided by 2 both sides, we get

⇒ $x\°+(3x+7)\°=90\°$

⇒ $x\°+3x+7\°=90\°$

⇒ $4x=90\°-7\°$

⇒ 4x = $83\°$

⇒ $x=\dfrac{83\°}{4}$

⇒ $x=20.75\°$

∴ The value of x = $20.75\°$

Thus, the required "option B) $20.75\°$ " is correct.

7 0

3 years ago

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Help,, i’m in the middle of a test and i need this answer!

gayaneshka [121]

Answer:

Step-by-step explanation:

brainlest pls

6 0

2 years ago

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Help me write this two numbers in words 1,328,800,16 15,802

Zigmanuir [339]

one hundred thirty two million, eight hundred eighty thousand and sixteen

(Your commas are in the incorrect spot)

fifteen thousand, eight hundred and two

7 0

3 years ago

A triangle with sides 11m , 13m and 18m is a right triangle. A True B False

Julli [10]

$\bold{\huge{\pink{\underline{ Solution}}}}$

$\bold{\underline{ Given :-}}$

A triangle with sides 11m, 13m and 18m

$\bold{\underline{ To \: Find :-}}$

We have to check it whether it is right angled triangle or not?

$\bold{\underline{ Let's \: Begin :-}}$

$\sf{\red{ In \:right \:angled\ : triangle, }}$

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

We imply it in the given triangle ,

$\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}$