1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lana71 [14]
3 years ago
12

Anyone know what the answer to this is?

Mathematics
2 answers:
MariettaO [177]3 years ago
8 0
It's the 3rd answer

1 \div (36a^{4}{b}^{10} )
maks197457 [2]3 years ago
3 0

Answer:   \bold{c)\ \dfrac{1}{36\cdot a^{4}\cdot b^{10}}}

<u>Step-by-step explanation:</u>

Use the power rule for exponents - (multiply the exponents).

Then move all of the terms that have a negative exponent to the other side of the fraction bar and change the sign of the exponent.

\bigg(\dfrac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}}\bigg)^{-1}\\\\\\\\\text{distribute the exponent of -1 to both the top and bottom of the fraction:}\\=\dfrac{(2a^{-3}b^4)^{-2}}{(3a^5b)^{2}}\\\\\\\text{Now, distribute the exponent of -2 to the top and 2 to the bottom:}\\=\dfrac{2^{-2}\cdot a^{6}\cdot b^{-8}}{3^2\cdot a^{10}\cdot b^2}

\text{Next, move }2^{-2}\ \text{and}\ b^{-8}\ \text{to the other side of the fraction}\\\text{bar and change the sign of the exponent.}\\\\=\dfrac{a^6}{2^2\cdot 3^2\cdot a^{10}\cdot b^2\cdot b^8}\\\\\\\text{Simplify }2^2\cdot3^2\ (4\cdot 9 = 36),\ \text{use the exponent rules for multiplying}\\ \text{terms that have the same base (add the exponents), and the exponent}\\\text{rules for dividing terms that have the same base (subtract the exponents).}\\\\=\dfrac{1}{36\cdot a^{10-6}\cdot b^{2+8}}

=\dfrac{1}{36\cdot a^{4}\cdot b^{10}}

You might be interested in
guys, pleasee please can somebody who is good at school help me please, im failing, im behind and my mom is going to hit me agai
hodyreva [135]

Answer:

wha-

Step-by-step explanation:

usususujsjsjsjsisiisjs

3 0
2 years ago
Dex estimates that 49,892 ÷ 0.89 is about 5,000. Is his estimate reasonable? Why or why not?
SVEN [57.7K]

Answer:yes

Step-by-step explanation:

because 0.89 is a very small number so itd be reasonable for it to be a large number

3 0
2 years ago
Read 2 more answers
The equation of a circle is given below. Identify the center and radius. Then graph the circle.
Blizzard [7]

Answer:

  • Center = (3, 0)
  • Radius = 3
  • Graph = see below

Concept:

Here, we need to know the idea of the circle equation.

Circle equation: (x - h)² + (y - k)² = r²

(h, k) = center

r = radius

x = variable

y = variable

Solve:

<u>Given expression </u>

(x - 3)² + y² = 9

<u>Find the point of the center</u>

(h, k) = \boxed{(3,0)}

<u>Find the length of the radius</u>

r² = 9

\boxed{r=3}

Hope this helps!! :)

Please let me know if you have any questions

3 0
2 years ago
Read 2 more answers
If f (x) = -2x2 + 6, find f (-3).
Margarita [4]

Answer:

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
If a system including the quadratic equation representing the parabola and a linear equation has no solution, which linear equat
marshall27 [118]

9514 1404 393

Answer:

  D.  y=2x+6​

Step-by-step explanation:

The line cannot intersect the parabola if it has a y-intercept greater than 5 and a suitable slope. The only sensible answer choice is ...

  y = 2x +6

7 0
2 years ago
Read 2 more answers
Other questions:
  • Match equivalent trigonometric ratios.
    6·1 answer
  • PPPPPPPPPPPLLLLLLLLLLZZZZZZZ HELPPPPP I WILL GIVE 50 POINTS
    14·2 answers
  • Question 10 Multiple Choice Worth 1 points)
    11·1 answer
  • Express 0.0000000734 in scientific notation.
    12·1 answer
  • Find a basis for the row space and column space of a matrix and the rank .
    15·1 answer
  • Write an equation of the line shown. Then use the equation to find the value of x when y = 150​
    7·1 answer
  • Help plzzzzzzzzzzzzzz
    6·1 answer
  • A donut has a diameter of 7 in. What is the radius?
    5·2 answers
  • Please help thank you
    14·2 answers
  • Find the missing side.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!