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3 years ago

Find the minimum, first quartile, median, third quartile, and maximum of each data set, 12, 10, 11, 7, 9, 10, 5

2 answers:

7 0

To find the median:
Least to greatest order:

5, 7, 9, 10, 10, 11, 12

10 is the number in the middle. Therefore the median is 10

cricket20 [7]3 years ago

3 0

Minimum : the smallest # ; 5

Maximum : the biggest # ; 12

Median : the "middle" # ; 10

1st Quartile : the median of the #'s before the median ; 7

3rd Quartile : the median of the #' s after the median ; 11

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

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Ann and ben had some apples. The ratio of the number of Ann's apples to the ratio of Ben's apple is 2:3. Ann gave 6 apples to be

aleksklad [387]

Answer:

There are 12 apples in total.

Step-by-step explanation:

If Anne gave Ben 6 apples then heres how:

2:3 subrtact 6 apples = 1:3

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3 years ago

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Tcecarenko [31]

Answer:

5 & 1

Step-by-step explanation:

We can use the quadratic formula to solve this:

Quadratic Formula = $\frac{-b+-\sqrt{b^2-4ac} }{2a}$

So we will have 2 answers (roots).

a is the coefficient of x^2 (2)

b is the coefficient of x (-12)

c is the constant (10)

Now, substituting, we get:

x = $\frac{-b+-\sqrt{b^2-4ac} }{2a}=\frac{12+-\sqrt{(-12)^2-4(2)(10)} }{2(2)}=\frac{12+-\sqrt{64} }{4}=\frac{12+-8}{4}=\frac{12+-8}{4}=5,1$

Hence the roots are 5 & 1

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