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ZanzabumX [31]
3 years ago
14

Four is no less then the quotient of a number x and 2.1

Mathematics
1 answer:
Alecsey [184]3 years ago
8 0

X/2.1<4  X<4×2.1  X<8.4

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Researchers doing a study comparing time spent on social media and time spent on studying randomly sampled 200 students at a maj
Charra [1.4K]

Answer:

d. 0.0023

Step-by-step explanation:

Calculation for the probability of getting a sample average of 1.8 or less

Using this formula

z score =(X-mean)/Standard errror

Where,

Standard error =Standard deviation/√(n)

Let plug in the formula

P(Xbar<1.8)=P(Z<(1.8 hours per day -2.2 hours per day)/(2 hours /√(200))

P(Xbar<1.8)=P(Z<-0.4/(2/14.14))

=P(Z<-0.4/0.1414)

=P(Z<-2.83)

Now let find the Z score of P(Z<-2.83) using the z table

P=0.0023

Therefore the probability of getting a sample average of 1.8 or less is:0.0023

5 0
3 years ago
Angle A and angle B are supplementary. The measure of angle B is 82.5.
stealth61 [152]

Answer:

Angle A = 97.5º

Step-by-step explanation:

Supplmentary means 2 angles that equal 180º. So we already have 1 angle, so now all we have to do is subtract 82.5 from 180.

180 - 82.5 = 97.5

5 0
3 years ago
Read 2 more answers
10 times for thousands equals blank thousand equals blank
Marianna [84]
10×4,000=40,000 because all u do is add an extra zero everything you multiple something by ten
5 0
3 years ago
In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.
WARRIOR [948]

Answer:

For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

y_2(t)=cosht  is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

3 0
3 years ago
18 is ______percent of 40
user100 [1]

Answer:

18 is 45% of 40

Step-by-step explanation:

3 0
3 years ago
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