Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,
xz_007 [3.2K]
The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.
<h3>How to determine the range of a function?</h3>
Given: 12x + 6y = 24
Here x stands for the input and y stands for the output
Replacing y with f(x)
12x + 6f(x) = 24
6f(x) = 24 - 12x
f(x) = (24 - 12x)/6
Domain = {-4, 0, 5}
Put the elements of the domain, one by one, to estimate the range
f(-4) = (24 - 12((-4))/6
= (72)/6 = 12
f(0) = (24 - 12(0)/6
= (24)/6 = 4
f(5) = (24 - 12(5)/6
= (-36)/6 = -6
The range exists {12, 4, -6}
Therefore, the correct answer is option c. {12, 4, -6}.
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Answer:
I think you meant for the plus sign in the second problem to be an = sign so the equation looks like this y=-x+4
If so your answer is A the first graph
I graphed it on desmos calculator
X/50 = 20/100
its takes adding 30 to 20 to get to 50 so add 30 to 100 then its 130/100 (130 over 100) and then divide that and its 13 = 13%
i think its right dont hold it against me if im wrong
Answer:
103 students live 1 mile away from the school.
Step-by-step explanation:
First dicide what the problem is really asking you then you end up getting divisoin them divide 515/3.