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wlad13 [49]
3 years ago
15

9) WILL MARK BRAINLIEST + 10 POINTS. Please help with question. :)

Mathematics
2 answers:
Masja [62]3 years ago
6 0
Answer is A.
√6 + √2
-----------
    4
Alex_Xolod [135]3 years ago
4 0
The answer is A.
sin(105)=0.96592
Answer A=0.96492

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Please add this problem 4 5/6 + 6/7=
sweet [91]
Convert to a mixed number:
239/42

Divide 239 by 42:
4 | 2 | 2 | 3 | 9

42 goes into 239 at most 5 times:
 | | | | 5
4 | 2 | 2 | 3 | 9
 | - | 2 | 1 | 0
 | | | 2 | 9

Read off the results. The quotient is the number at the top and the remainder is the number at the bottom:
 | | | | 5 | (quotient)
4 | 2 | 2 | 3 | 9 | 
 | - | 2 | 1 | 0 | 
 | | | 2 | 9 | (remainder)


The quotient of 239/42 is 5 with remainder 29, so:

Answer: 5 29/42
7 0
3 years ago
Read 2 more answers
The vertices of a triangle are A (-2, 2), B (4,10), and C (0, -2). Find the equation of the line that contains
Tpy6a [65]

Answer:

y = 1/2 x + 3

Step-by-step explanation:

mid point of line BC = (2, 4)

slope of the line containing median (m) = 1/2

y intercept (b)= 3

since y = mx + b

y = 1/2x + 3

4 0
3 years ago
How would you graph the solution set of ≤ -18?
maxonik [38]
Using a graph !!!!!!!!
6 0
2 years ago
Noah and Lin are each trying to solve the equation x² - 6x + 10 = 0. They know that the solutions to x² = - 1 are i and -i, but
Leviafan [203]

Answer:

Solving the equation x^2 - 6x + 10 = 0 we get x=3+i \ , \ x=3-i

Step-by-step explanation:

Noah's step to solve the equation x^2 - 6x + 10 = 0 are:

x^2 - 6x + 10 = 0\\x^2 - 6x = -10\\x^2 - 6x + 9 = -10 + 9\\(x-3)^2 = -1

The next step is to take square root on both sides because: \sqrt{x^2}=x

\sqrt{(x-3)^2}=\sqrt{-1}  \\x-3=\pm\sqrt{-1} \\x=\pm(\sqrt{-1})+3 \\

Now, we know that: \sqrt{-1}=i

x=\pm(i)+3\\x=3+i \ , \ x=3-i

So, Solving the equation x^2 - 6x + 10 = 0 we get x=3+i \ , \ x=3-i

8 0
3 years ago
Which system of linear inequalities is represented by the graph?
masha68 [24]
For the red line, we have:
 
gradient (m) = 1/3
y-intercept = 3

Equation of straight line is given by y=mx+c, where m is the gradient and c is where the line intercept the y-axis

So we have, y= \frac{1}{3}x+3

The shaded part is above the line, hence the first inequality is
y \geq \frac{1}{3}x+3

The black line, we have
gradient, (m) = 3
y-intercept = -2

y=mx+c
y=3x-2, rearranging gives
3x-y=2

The shaded region is to the right of the line, hence the inequality is
3x-y\ \textgreater \ 2

Note: The first option should be the correct answer but the inequality sign for <span>y > 1/3x + 3 should be </span>\geq 



6 0
3 years ago
Read 2 more answers
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