One nice thing about this situation is that you’ve been given everything in the same base. To review a little on the laws of exponents, when you have two exponents with the same base being:
– Multiplied: Add their exponents
– Divided: Subtract their exponents
We can see that in both the numerator and denominator we have exponents *multiplied* together, and the product in the numerator is being *divided* by the product in the detonator, so that translates to *summing the exponents on the top and bottom and then finding their difference*. Let’s throw away the twos for a moment and just focus on the exponents. We have
[11/2 + (-7) + (-5)] - [3 + 1/2 + (-10)]
For convenience’s sake, I’m going to turn 11/2 into the mixed number 5 1/2. Summing the terms in the first brackets gives us
5 1/2 + (-7) + (-5) = - 1 1/2 + (-5) = -6 1/2
And summing the terms in the second:
3 + 1/2 + (-10) = 3 1/2 + (-10) = -6 1/2
Putting those both into our first question gives us -6 1/2 - (-6 1/2), which is 0, since any number minus itself gives us 0.
Now we can bring the 2 back into the mix. The 0 we found is the exponent the 2 is being raised to, so our answer is
2^0, which is just 1.
Answer:
Ecuaciones algebraicas. De primer grado o lineales. De segundo grado o cuadráticas...
Ecuaciones trascendentes, cuando involucran funciones no polinómicas, como las funciones trigonométricas, exponenciales, logarítmicas, etc.
Ecuaciones diferenciales. Ordinarias...
Ecuaciones integrales.
Ecuaciones funcionales.
Hope this helps! :)
The link is in the other answer
Answer:
Step-by-step explanation:
![\frac{x+2}{4x^2 + 5x + 1} \ \times \ \frac{4x+1}{x^2-4}\\\\=\frac{x+2}{4x^2 + 4x + x + 1} \ \times \ \frac{4x+1}{x^2-2^2}\\\\=\frac{x+2}{4x(x + 1) + 1( x + 1)} \ \times \ \frac{4x+1}{(x - 2)(x + 2)} \ \ \ \ \ \ \ \ [ \ (a^2 - b^2 = (a-b)(a+b) \ ]\\\\\\=\frac{x+2}{(4x + 1)(x+1)} \ \times \ \frac{4x+1}{(x-2)(x+2)}\\\\=\frac{1}{(x+1)} \ \times \ \frac{1}{(x-2)}\\\\= \frac{1}{(x+1)(x-2)}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B2%7D%7B4x%5E2%20%2B%205x%20%2B%201%7D%20%5C%20%5Ctimes%20%5C%20%5Cfrac%7B4x%2B1%7D%7Bx%5E2-4%7D%5C%5C%5C%5C%3D%5Cfrac%7Bx%2B2%7D%7B4x%5E2%20%2B%204x%20%20%2B%20x%20%2B%201%7D%20%5C%20%5Ctimes%20%5C%20%5Cfrac%7B4x%2B1%7D%7Bx%5E2-2%5E2%7D%5C%5C%5C%5C%3D%5Cfrac%7Bx%2B2%7D%7B4x%28x%20%2B%201%29%20%20%2B%201%28%20x%20%2B%201%29%7D%20%5C%20%5Ctimes%20%5C%20%5Cfrac%7B4x%2B1%7D%7B%28x%20-%202%29%28x%20%2B%202%29%7D%20%20%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5B%20%5C%20%28a%5E2%20-%20b%5E2%20%3D%20%28a-b%29%28a%2Bb%29%20%5C%20%5D%5C%5C%5C%5C%5C%5C%3D%5Cfrac%7Bx%2B2%7D%7B%284x%20%2B%201%29%28x%2B1%29%7D%20%5C%20%5Ctimes%20%5C%20%5Cfrac%7B4x%2B1%7D%7B%28x-2%29%28x%2B2%29%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B%28x%2B1%29%7D%20%5C%20%5Ctimes%20%5C%20%5Cfrac%7B1%7D%7B%28x-2%29%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B1%7D%7B%28x%2B1%29%28x-2%29%7D)
