What is the answer to this problem?

Help please!! I will mark brainilist and give a lot of points.

julia-pushkina [17]

Answer:

a = 23.588

Step-by-step explanation:

a^2 = 17 1/3^2 + 16^2

a^2 = 300.4 + 256

a^2 = 556.4

a = 23.588 (I rounded to thousandths but you can round to whatever)

8 0

2 years ago

Read 2 more answers

A burst of electromagnetic radiation has a frequency of 1 exahertz. One exahertz equals 10^12 megahertz. Each megahertz is equal

den301095 [7]

Answer:

The frequency of the burst of electromagnetic radiation which equals 1 exahertz = 10¹⁸ hertz.

Step-by-step explanation:

Since the frequency of the burst of electromagnetic radiation is 1 exahertz, and 1 exahertz = 10¹² megahertz. So, the frequency of radiation is 10¹² megahertz. Also 1 megahertz = 10⁶ hertz. So, 10¹² megahertz = 10¹² × 1 megahertz = 10¹² × 10⁶ hertz = 10¹² ⁺ ⁶ hertz = 10¹⁸ hertz.

So the frequency of the burst of electromagnetic radiation which equals 1 exahertz = 10¹⁸ hertz.

3 0

3 years ago

Question 10

kozerog [31]

The regular selling price per unit for the laptop is $298.6.

<h3>How to calculate the price?</h3>

Let the regular price per unit be x.

The expense is 19% of the selling price and profit is 25% of the selling price. This will be illustrated as:

x + (19% × x) + (25% × x) = 430

x + 0.19x + 0.25x = 440

1.44x = 430

Divide

x = 430 / 1.44

x = 298.6

The price is $298.6

Learn more about cost on:

brainly.com/question/25109150

#SPJ1

7 0

1 year ago

What is the solution to the system of equations? <br><br>6x+2y=6<br><br>7x+3y=5

Stells [14]

The answer is (2,-3)

4 0

3 years ago

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In college basketball, a shot made from beyond a designated arc radiating about 20 ft from the basket is worth three points ins

denis-greek [22]

Answer:

a) By the Central Limit Theorem, the distribution would be approximately normal, with mean $\mu = 0.45$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497$

b) 4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered surprising, so yes, it would be surprising for him to make only 25 of these shots.

Step-by-step explanation:

To solve this question, we are going to need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions, we have that the mean is $\mu = p$ and the standard deviation is $s = \sqrt{\frac{p(1-p)}{n}}$

In this problem, we have that:

$p = 0.45, n = 100$

a)By the Central Limit Theorem, the distribution would be approximately normal, with mean $\mu = 0.45$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497$

b)This is Z when X = 0.25.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.25 – 0.45}{0.0497}$

$Z = -4.02$

4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered

surprising, so yes, it would be surprising for him to make only 25 of these shots.

3 0

3 years ago