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xeze [42]
3 years ago
6

What is the answer to this problem?

Mathematics
1 answer:
yarga [219]3 years ago
3 0
Try this:
V=a³=6.2³=238,328 in.³
Answer: A.
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The shadow of a 5-foot tall post is 10 feet long. at the same time, a tree casts a shadow that is 22 feet long. what is the heig
FromTheMoon [43]
Because the shadow doubled, the tree is actually only 11 FEET TALL.
3 0
3 years ago
Read 2 more answers
The Software Company earned 2,247,852,199 dollars last year. This year they earned 3,000,962,245 dollars. Which is the best esti
RSB [31]

You know the following information:

1. The amount of money (in dollars) earned last year was:

2,247,852,199

2. The amount of money (in dollars) earned this year, is:

3,000,962,245

Then, to estimate the sum (the total amount of money the Software Company earned in those two years, you can round the numbers to the nearest billion.

Having:

2,247,852,199

You need to look at the digit located in the Hundred millions place. Notice that this is:

2

Then, since:

2

You need can't round up. Then:

2,247,852,199\approx2,000,000,000

Now, having:

3,000,962,245

You can identify that the digit in the Hundred millions place is

0

Therefore:

3,000,962,245\approx3,000,000,000

Now you can add the numbers rounded:

2,000,000,000+3,000,000,000=5,000,000,000

Hence, the answer is: Option B.

5 0
1 year ago
Pls help I’m begging u
OlgaM077 [116]

You're answer is the third one, you gotta divide the money by the hours worked and then compare.

3 0
3 years ago
E=6c^2-2c-1<br> F=-4c^2+7c+5<br> E+F=
kifflom [539]

Answer:

E + F =   2c^2  + 5c + 4

Step-by-step explanation:

E=6c^2-2c-1

F=-4c^2+7c+5

E+F=  6c^2   -2c   -1  +  -4c^2   +   7c   +  5

E + F =   6c^2 - 4c^2  - 2c + 7c  - 1  + 5

E + F =   2c^2  + 5c + 4

4 0
3 years ago
Determine the asymptotes of the function: y=x^3-5x^2+4x-25/x^2-4x+3
igomit [66]

Answer:

Vertical A @ x=3 and x=1

Horizontal A nowhere since degree on top is higher than degree on bottom

Slant A @ y=x-1  

Step-by-step explanation:

I'm going to look for vertical first:

I'm going to factor the bottom first:  (x-3)(x-1)

So we have possible vertical asymptotes at x=3 and at x=1

To check I'm going to see if (x-3) is a factor of the top by plugging in 3 and seeing if I receive 0 (If I receive 0 then x=3 gives me a hole)

3^3-5(3)^2+4(3)-25=-31 so it isn't a factor of the top so you have a vertical asymptote at x=3

Let's check x=1

1^3-5(1)^2+4(1)-25=-25 so we have a vertical asymptote at x=1 also

There is no horizontal asymptote because degree of top is bigger than degree of bottom

There is a slant asympote because the degree of top is one more than degree of bottom (We can find this by doing long division)

                       x   -1

                --------------------------------------------------

x^2-4x+3 |      x^3-5x^2+4x-25

                  - ( x^3-4x^2+3x)

                   --------------------------------

                            -x^2 +x  -25

                       -   (-x^2+4x-3)

                          ---------------------

                                   -3x-22

So the slant asymptote is to x-1

8 0
3 years ago
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