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stiv31 [10]
3 years ago
11

8 cm 10 cm 3 cm 12 cm Work out the shaded area of the shape?

Mathematics
1 answer:
qwelly [4]3 years ago
6 0

Answer:

36 sq. cm

Step-by-step explanation:

triangle area= 0.5 * 12* 10

rectangle are= 8* 3

60 - 24 = 36

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Hellppp me this is hard​
ad-work [718]

Answer:

f

Step-by-step explanation:

its is that because it would mean he would be going 65 whuch its asking for a general speed.

8 0
3 years ago
Analyze the diagram below and complete the instructions that follow?
yan [13]

Answer:

The exact value of tan(M) is 5/12 ⇒ answer (C)

Step-by-step explanation:

* Lets revise the trigonometry functions

- In ΔABC

# m∠B = 90°

# Length of AB = a , length of BC = b and length of AC = c

# The trigonometry functions of angle C are

- sin(C) = a/c ⇒ opposite side to ∠C ÷ the hypotenuse

- cos(C) = b/c ⇒ adjacent side to ∠C ÷ the hypotenuse

- tan(c) = a/b ⇒ opposite side to ∠C ÷ adjacent side to ∠C

* Now lets solve the problem

- In ΔONM

∵ m∠N = 90°

∵ MN = 12

∵ ON = 5

∵ tan(M) = ON/NM ⇒ opposite side of ∠(M) ÷ adjacent side of ∠(M)

∴ tan(M) = 5/12

* The exact value of tan(M) is 5/12

6 0
3 years ago
Which statement is true for the equation 4n − 3 = 4n − 2?
Tems11 [23]
It has no solutions. Hope it helps
7 0
2 years ago
Read 2 more answers
To find the interquartile range you need to ____the upper and lower quartile values.​
Blababa [14]

Answer:

The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median

8 0
2 years ago
Read 2 more answers
Please show work for both problems
kirill [66]

Answer:

3)  x = 15; 95 and 85      4)  x = 12; 98 for both angles

Step-by-step explanation:

2x + 65 + 3x + 40 = 180       Set the equations equal to 180

5x + 105 = 180                      Combine like terms

     - 105  - 105                      Subtract 105 from both sides

5x = 75                                  Divide both sides by 5

x = 15

Plug 15 into both equations

2(15) + 65 = 95

3(15) + 40 = 85

4)  5x + 38 = 9x - 10             Set the equations equal to each other

  - 5x          - 5x                    Subtract 5x from both sides

 38 = 4x - 10

+ 10       + 10                         Add 10 to both sides

48 = 4x                                  Divide both sides by 4

12 = x

Plug 12 into both equations

5(12) + 38 = 98

9(12) - 10 = 98

6 0
2 years ago
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