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3 years ago

how much force does it take to push a 62.0 kg dresser at a constant speed across a carpet with µk=0.238. (unit=N)

Physics

2 answers:

Gnesinka [82]3 years ago

7 0

Answer:

Force, F = 144.6 N

Explanation:

It is given that,

Mass of the dresser, m = 62 kg

Coefficient of kinetic friction, $\mu_k=0.238$

We need to find force with which the dresser is pushed. It is given by :

$F=\mu mg$

$F=0.238\times 62\times 9.8$

F = 144.6 N

So, the force taken by the dresser is 144.6 N. Hence, this is the required solution.

Mama L [17]3 years ago

3 0

Answer:

158.76504N

Explanation:

F = µk * m * g

F = 0.238 * 62 * 9.81

F = 158.76504N

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