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Doss [256]
4 years ago
7

What units are used to measure force

Physics
2 answers:
spayn [35]4 years ago
8 0
In the metric system, the most common unit used is a Newton, which is a (kg x m)/sec^2 and in the English system, the most common unit is a Pound, which is a (slug x ft)/sec^2.

But really, any unit that conforms to a the diagram of a mass times a length divided by a time squared can be used to measure force. A microgram x kilometer divided by decade^2 is also a unit to measure force, albeit a very ugly one. I hope this helps :)
Nastasia [14]4 years ago
5 0
N, or Neutons are a common way to measure force
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There must be a centripetal force to move the object move in a curve path.
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3 years ago
Read 2 more answers
An Olympic track runner starts from rest and has an acceleration of 2.4 m/s2 for 3.6 s, then has zero acceleration for the remai
rjkz [21]

Answer:

The runner's speed at the following times would remain 8.64 m/s.

Explanation:

Acceleration definition: Acceleration is rate of change in velocity of an object with respect to time.

In this case, after 3.6 seconds the acceleration is zero, it means that the velocity of the runner after 3.6 seconds is not changing and it will remain constant for the remainder of the race. Now, we have to find the velocity of the runner that he had after 3.6 seconds and that would be the runner's speed for the remainder of the race. For this we use first equation of motion.

First equation of motion:        Vf = Vi + a×t

Vf stands for final velocity

Vi stands for initial velocity

a stands for acceleration

t stands for time

In the question, it is mentioned that the runner starts from rest so its initial velocity (Vi) will be 0 m/s.

The acceleration (a) is given as 2.4 m/s²

The time (t) is given as 3.6 s

Now put the values of Vi, a and t in first equation of motion

                       Vf = Vi + a×t

                       Vf = 0 + 2.4×3.6

                       Vf = 2.4×3.6

                       Vf = 8.64 m/s

So,the runner's speed at the following times would remain 8.64 m/s.

5 0
3 years ago
In a fit of rage about distance learning, you throw your computer out the window with an initial velocity of 3 m/s and it breaks
lesya692 [45]

Answer:

9 m

Explanation:

i did the test and got 100%

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3 years ago
A 1.0-kg ball is attached to the end of a 2.5-m string to form a pendulum. This pendulum is released from rest with the string h
hram777 [196]

Answer:

v_{2}=3.5 m/s

Explanation:

Using the conservation of energy we have:

\frac{1}{2}mv^{2}=mgh

Let's solve it for v:

v=\sqrt{2gh}

So the speed at the lowest point is v=7 m/s

Now, using the conservation of momentum we have:

m_{1}v_{1}=m_{2}v_{2}

v_{2}=\frac{1*7}{2}

Therefore the speed of the block after the collision is v_{2}=3.5 m/s

I hope it helps you!

       

8 0
3 years ago
Is it possible to put a distance versus time graph to be universal go mine
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Yes I'm pretty sure you can
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