Answer:
B
Step-by-step explanation:
2 || 1 - 4 6 - 4
2 -4 4
==================
1 -2 2
x^2 - 2x + 2 with no remainder.
Looks like the answer is B
Note: Note that the two in x - 2 changes sign. That always happens when using synthetic division as long the number in front of the x is positive.
The expression is
5x + 5y
We are to prove that it is an odd integer when x and y are integers of opposite parity
First, we can assume
x = 2a (even)
y = 2b + 1(odd)
subsituting
10(a + b) + 5
5 [(2(a + b) + 1]
The term
2(a + b) + 1 is odd and the result of an odd number multiplied by an odd number is odd
2x + 7 ≤ 3x - 5
Start by keeping the variable x on the left side of the inequality, and move everything else to the right side.
We can do this by subtracting 3x from both sides and subtracting 7 from both sides.
-x ≤ -12
Divide both sides by -1 to make x a positive; when dividing by a negative number you will flip the inequality sign, so ≤ becomes ≥.
x ≥ 12
Possible solutions for x are any number equal to or greater than 12.
$2.50
Hope this helps!
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- Hypotenuse= ML
- Perpendicular=KL=15
- Base= KM=8
By using Pythagoras theorem.
- h²=p²+b²
- ML²=15²+8²
- ML²=225+64
- ML=√289
Therefore ML= 17...
Step-by-step explanation:
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