What is quotient of a number 21

Classify the triangle with 9, 15, 19 as an acute right obtuse or not a triangle

Novosadov [1.4K]

Answer:

Hence the correct option is the last one . The triangle is an obtuse angled triangle.

Step-by-step explanation:

i) the sum of any two sides added together is greater than the third side hence this is a triangle.

ii) it is not a right angled triangle as $\sqrt{9^{2} + 15^{2} } \neq 19$ and $\sqrt{9^{2} + 15^{2} } < 19$

iii) the triangle is not acute from ii) above

iv) the triangle is an obtuse triangle from ii) above.

8 0

3 years ago

There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the sampling distribution of the sampling proportions.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

3 years ago

Enrico is filling his pool. The pool has 3,000 gallons of water now. The water hose used by Enrico puts 500 gallons per hour in

Feliz [49]

Answer:

3,000=500x

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Given the figure. Find AC.

Angelina_Jolie [31]

Image is missing, so i have attached it.

Answer:

AC = 10sin 40°

Step-by-step explanation:

From the diagram attached, using terms in trigonometric ratio, AC is the opposite side, BC is the adjacent side and AB is the hypotenuse.

Thus, since we want to find AC;

We know that in trigonometric ratios; opposite/hypotenuse = sin θ

In the diagram, θ = 40° and AB = 10

Thus,

AC/10 = sin 40°

Multiply both sides by 10 to get;

AC = 10sin 40°

7 0

4 years ago

I want to find the coordinates of each point of the face

Sergio039 [100]

Answer:

A) (2,5)

B) (4,4)

C) (3,2)

D) (3,-1)

E) (1,-3)

F) (-1,-3)

G) (-3,-1)

H) (-3,2)

I) (-4,4)

J) (-2,5)

K) (-1,4)

L (1,4)

7 0

3 years ago