<span>1/5
This is a matter of elimination. So let's figure out how many of each display there is.
30% of 150 = 0.30 * 150 = 45 displays about electricity.
2/5 * 150 = 0.40 * 150 = 60 displays about renewable energy
1/10 * 150 = 150/10 = 15 displays about gas.
The rest of the displays are about nuclear power. So
150 - 45 - 60 - 15 = 30 displays about nuclear power. Since we want a fraction, we get 30/150
But 30/150 isn't in it's simplest form. The largest number that will evenly divide both 30 and 150 is 30. So divide both the numerator and denominator by 30
(30/30)/(150/30) = 1/5
So 1/5 of the displays are about nuclear power.</span>
Summary of problem.
annual production = 60000 units
work hours per worker = 200*12=2400 hours
productivity = 0.15 unit / person-hour
Need to calculate the number of workers/persons employed.
Each unit requires 1 unit / 0.15 unit/person-hour
= 1/0.15 person-hours / unit
60000 unit requires 60000 units * 1/0.15 person-hours/unit
= 400000 person-hours
400000 person-hours requires 400000 person-hours /2400 hours = 166.7 persons
=>
The plant has 167 labourers (assuming perfect attendance).
Answer:
Step-by-step explanation:
4x + y = - 1 -------------(I)
-5x - 2y = -4 -----------(II)
Multiply the equation (I) by 2 and then add the equations.
(I)*2 8x + 2y = -2
(II) <u>-5x - 2y = -4</u> {Now add and y will be eliminated}
3x = -6
x = -6/3
x = -2
Substitute x = -2 in equation (I)
4*(-2) + y = -1
-8 + y = -1
y = - 1 + 8
y = 7
Answer:
y=1/2x-2
Step-by-step explanation:
Answer:
A. &. D
Step-by-step explanation:
Open and to the right.
