The additive inverse of a complex z is a complex number
so that
Finding
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Tags: <em>complex number additive inverse opposite algebra</em>
Answer:
h(x - 1) = -5x - 2
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Terms/Coefficients
Functions
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
h(x) = -5x - 7
<u>Step 2: Find</u>
- Substitute in <em>x </em>[Function h(x)]: h(x - 1) = -5(x - 1) - 7
- [Distributive Property] Distribute -5: h(x - 1) = -5x + 5 - 7
- Combine like terms: h(x - 1) = -5x - 2
2x-4y=-16
ax+4y=6 +
--------------------
2x+ax=-10; for x=-2,
2(-2)+a(-2)=-10
-2a=-10+4
a=-6/-2
a=3
Answer:
13
Step-by-step explanation:
3h - j
3(8) - 11
24 - 11
13
Answer:
y² -7y+12
Step-by-step explanation:
first, you have to multiply each character on the first parenthesis to the second one, one by one. just like the picture attached.
then, combine all of the same variable. like the 2 variable that has y.
