the first one on the left row to the 3rd one in the right row
the second one on the left row to the top one in the right row
the third one on the left row to the middle one in the right row
Sure hope this helps
Answer:
These type of people on brainly are what I live for L M A O
Explanation:
Devmgmt.msc is what u would enter in dialog box to open device manager console
Start with your name and contact information, use a font that’s easy to read, and keep the format consistent
Answer: The message must be sent 9.313 approximately 9 times to get the entire data through.
Explanations: To find how many times the message must be sent on average to avoid error control in data link later.
E = 1/P
E = The average number of attempt before successful transmission.
P= Total probability of transmission without error.
STEP1 : FIND TOTAL PROBABILITY;
Since it each frame has a probability of 80% to be successful.
For each frame p = 80/100 = 0.8
For the 10 frame; total probability
P= (0.8)^10 = 0.1074
STEP2: FIND THE AVERAGE NUMBER OF OF TRIAL BEFORE A SUCCESSFUL TRANSMISSION WITHOUT ERROR;
Using equation above
E = 1/P
E= 1 ÷ 0.1074 = 9.313
Therefore they must be an average of 9.313 approximately 9 trials before a successful transmission without error.