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schepotkina [342]
3 years ago
15

all I drink 3/4 of a 16 fluid ounce bottle of juice how many fluid ounces of juice are left in the bottle

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
5 0
4 fluid ounces. 16 * 1/4 is 4
mart [117]3 years ago
3 0
STEP 1:
multiply 16 oz. by 3/4 to find how many ounces are 3/4 of the bottle

=16 * 3/4
=(16*3)/4
=48/4
=12 ounces


STEP 2:
subtract step 1 answer from the whole 16 oz. to find number of ounces left

=16 - 12
=4 ounces left


CHECK:
multiply the whole 16 oz. by the fraction that would be left (4/4 - 3/4= 1/4). There are several ways to check this problem; this is just one way.

=16 * 1/4
=(16*1)/4
=16/4
=4


ANSWER: 4 ounces would be left

Hope this helps! :)
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In a one-tail hypothesis test where you reject h0 only in the upper tail, what is the p-value if z-stat= 1. 70?
11111nata11111 [884]

In a one-tail hypothesis test where you reject h0 only in the upper tail

-1.2910  is the p-value.

A p-value is a statistical measure used to test a hypothesis against observed data. The p-value measures the probability of getting the observed result given that the null hypothesis is true. The lower the p-value, the higher the statistical significance of the observed difference.

For null hypothesis significance tests, the p-value is the probability of obtaining an extreme test result that is at least as extreme as the actually observed result, given that the null hypothesis is true.

Learn more about p-value here: brainly.com/question/4621112

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5 0
1 year ago
WILL GIVE BRAINLIEST!!!!!!
Mumz [18]

Answer: 126 milligrams

Step-by-step Easy to answer but all your doing is converting your mg's and 35% into decimals. and you will get your answer

8 0
3 years ago
An SRS of ten brands of breakfast cereals is tested for the number of calories per serving. The following data result: 185, 190,
Pepsi [2]

Using the t-distribution, as we have the standard deviation for the sample, it is found that the 95% confidence interval estimate for the mean number of calories for servings of breakfast cereals is (195.3, 215.7).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm t\frac{s}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • t is the critical value.
  • n is the sample size.
  • s is the standard deviation for the sample.

From the sample and the significance level of 0.05, we have that the parameters are given by:

\overline{x} = 205.5, s = 14.2, n = 10, t = 2.2622

Hence:

\overline{x} - t\frac{s}{\sqrt{n}} = 205.5 - 2.2622\frac{14.2}{\sqrt{10}} = 195.3

\overline{x} + t\frac{s}{\sqrt{n}} = 205.5 + 2.2622\frac{14.2}{\sqrt{10}} = 215.7

The 95% confidence interval estimate for the mean number of calories for servings of breakfast cereals is (195.3, 215.7).

More can be learned about the t-distribution at brainly.com/question/16162795

8 0
2 years ago
What is the value of x in the equation 6(х + 1) — 5х = 8 + 2(x — 1)?
Licemer1 [7]

Multiply the first bracket by 6.

Multiply the second bracket by 8

6(x+1)-5x= 8+2(x-1)

6(x)+6(1)-5x= 8+2(x)+2(-1)

6x+6-5x= 8+2x-2

6x-5x+6= 8-2+2x

x+6= 6+2x

Move +2x to the other side. Sign changes from +2x to -2x.

x-2x+6= 6+2x-2x

-x+6= 6

Move +6 to the other side. Sign changes from +6 to -6.

-x+6-6= 6-6

-x=0

Multiply by -1 for -x and 0

-x(-1)= 0(-1)

x= 0

Answer: x= 0

6 0
3 years ago
The inches of rainfall in the rainforest is represented by the function f(x) = 3(x-2)+ 4. What is the average rate of change bet
nata0808 [166]

Answer:

The average rate of change of rainfall in the rainforest between 2nd year and 6th year = <u>3 inches</u>

Step-by-step explanation:

Given function representing inches of rainfall:

f(x)=3(x-2)+4

To find the average rate of change between the 2nd year and the 6th year.

Solution:

The average rate of change between interval [a,b] is given as :

\frac{f(b)-f(a)}{b-a}

For the given function we need to find the average rate of change between 2nd year and 6th year. [2,6]

So, we have:

f(2)=3(2-2)+4=3(0)+4=4

f(6)=3(6-2)+4=3(4)+4=12+4=16

Thus, average rate of change will be:

\frac{f(6)-f(2)}{6-2}

⇒ \frac{16-4}{6-2}

⇒ \frac{12}{4}

⇒ 3

Thus, the average rate of change of rainfall in the rainforest between 2nd year and 6th year = 3 inches

8 0
3 years ago
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