I would double check if I were you! Hope this helps!
In your town, there is a field that is in the shape of a right triangle with the dimensions shown. (Round answers to the nearest
1 answer:
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Answer:
Exponential Function:
Balance after
t=1 $ 13,524.32
t=2 $ 14,374.99
t=5 $ 17,261.69
t=10 $ 23,417.64
Step-by-step explanation:
Formula used to find amount in the account after time t, given the interest rate is compounded continuously
where: P= principal amount or amount invested
r= interest rate
t= time
A= amount after time t
in our question we are given:
P=$12,724
r= 6.1% or 0.061
The above equation is exponential function that describes the amount in the account after time t in years
Now, for t = 1
A= $ 13,524.32
t=2
A= $ 14,374.99
t= 5
A= $ 17,261.69
t=10
A= $ 23,417.64
Answer:
The true estimate of the average annual income of all 700 families living in a four square block section lies within the 92% confidence interval below
Step-by-step explanation:
From the question we are told that
The sample size is n = 50
The sample mean is
The population standard deviation is
From the question we are told the confidence level is 92% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of is
Generally the margin of error is mathematically represented as
=>
=>
Generally 92% confidence interval is mathematically represented as
=>
=>
So the true estimate of the average annual income of all 700 families living in a four square block section lies within the 92% confidence interval
Answer:
1. Equilibrium solution: y= -3
2. Equilibrium solution y= ±1.414
Step-by-step explanation:
Thinking process:
The equilibrium solution can only be derived when
1. Let's look at the first equation:
equating to the expression
gives
y + 3 = 0
y = -3
Therefore, the equilibrium solution occurs at y = -3
2. Let's look at the second solution:
dividing each side by (t²-1) gives
1/(t²-1) = (y²-2)/ (y²-4)
factorizing the right hand side gives:
at equilibrium: , then
y² - 2 = 0
solving for y gives y = ±√2
= ±1.414