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user100 [1]
4 years ago
15

What is the complex number z=−3+3√3i represented in polar form? z=____cis(____)

Mathematics
1 answer:
maks197457 [2]4 years ago
3 0

Answer:

<h2>6cis120°</h2>

Step-by-step explanation:

The general form of a complex number z = x+iy

If x = rcos\theta and y = rsin\theta

where r is the modulus of the complex number and \theta is the argument, z in polar form is represented as:

z =  rcos\theta+ rsin\theta

z = r(cos\theta+ isin\theta)

z = rcis\theta

Given the complex number z=−3+3√3i

r = \sqrt{x^{2}+y^{2}  }

r = \sqrt{(-3)^{2}+(3\sqrt{3})^{2}  } \\r = \sqrt{9+27} \\r = \sqrt{36}\\ r = 6

argument\\\theta = arctan \frac{y}{x} \\\theta = arctan \frac{3\sqrt{3} }{-3} \\\theta = arctan {-\sqrt{3} } \\\theta = -60 \deg

since the argument is negative and tan is negative in the 2nd and 4th quadrant,

In the second quadrant, theta = 180- 60 = 120°

On substituting r and theta, the complex number in polar form is expressed as 6cis120°

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• Second way to solve:

The degree of the function is 3. So, the function has 3 complex zeros.

Since the coefficients of the function are reals, the imaginary roots are in a even number (a imaginary number and its conjugated)

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3 0
3 years ago
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4vir4ik [10]

Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

3 0
3 years ago
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