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Archy [21]
4 years ago
14

An enclosure at the zoo contains 16 meerkats.

Mathematics
1 answer:
Elena L [17]4 years ago
3 0
Asleep. 6/16 Simplified would be 3/8

Awake. 10/16 Simplified would be 5/8

How I did it was by using the amount that was asleep and awake as numerators and the TOTAL is 16 so that is the denominator.

Hope this helps, let me know if you have any questions, have a good day!
You might be interested in
Some scientists believe alcoholism is linked to social isolation. One measure of social isolation is marital status. A study of
alexandr402 [8]

Answer:

1) H0: There is significant evidence of independence between marital status and diagnostic

H1: There is significant evidence of an association between marital status and diagnostic

2) The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

3) \chi^2 = \frac{(21-33.143)^2}{31.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

4) p_v = P(\chi^2_{2} >19.72)=0.00005222

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p values is lower than the significance level we have enough evidence to reject the null hypothesis at 5% of significance, and we can say that we have associated between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                    Alcoholic    Undiagnosed Alcoholic     Not Alcoholic   Total

Married             21                         37                               58                  116

Not Married      59                        63                               42                  164

Total                  80                        100                             100                 280

Part 1

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is significant evidence of independence between marital status and diagnostic

H1: There is significant evidence of an association between marital status and diagnostic

The level os significance assumed for this case is \alpha=0.05

Part 2

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{80*116}{280}=33.143

E_{2} =\frac{100*116}{280}=41.429

E_{3} =\frac{100*116}{280}=41.429

E_{4} =\frac{80*164}{280}=46.857

E_{5} =\frac{100*164}{280}=58.571

E_{6} =\frac{100*164}{280}=58.571

And the expected values are given by:

                    Alcoholic    Undiagnosed Alcoholic     Not Alcoholic   Total

Married         33.143                    41.429                        41.429              116

Not Married  46.857                   58.571                        58.571              164

Total                  80                        100                             100                 280

Part 3

And now we can calculate the statistic:

\chi^2 = \frac{(21-33.143)^2}{31.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

Part 4

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(2-1)(3-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.72)=0.00005222

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p values is lower than the significance level we have enough evidence to reject the null hypothesis at 5% of significance, and we can say that we have associated between the two variables analyzed.

8 0
3 years ago
Is the gsce foundation maths paper difficult or straight forward?
Sati [7]

Answer:

depends on how you understand math.

6 0
4 years ago
On her way to her grandmothers house, Jackie traveled 3 times as many miles by train as by bus. She travelled 4 times as many mi
Vera_Pavlovna [14]

Answer:

22 because it is just a train that they are talking about not how long it takes to get to grandmas house

3 0
3 years ago
Find equation of vertical line through (-5, -3)
Novay_Z [31]

Answer:

x = -5

Step-by-step explanation:

Given that it is a vertical line, we know that it will only go through one x-value.

We are also given a point, (-5, -3).

This point tells us that the vertical line only goes through the x-value -5, so the equation will be x = -5.

5 0
4 years ago
HELP PLEASE Connie can buy 48 roses for $120. Which is the cost per rose? A $1.20 B $2.50 © $3.00 D $4.00​
zubka84 [21]

Answer:

B: $2.50

Step-by-step explanation:

$120 ÷ 48 roses = cost per rose ($2.50)

4 0
3 years ago
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