Let the numbers be x and y. Then xy = -30 and x+y = -3.
Solve xy = -30 for y: y = -30/x
subst. -30/x for y in x+y= -3: x - 30/x = -3
Multiply all 3 terms by x: x^2 - 30 = -3x, so x^2 + 3x - 10 = 0
Solve this quadratic equation for x. x: {-5, 2}
If x = -5, then x+y = -3 becomes -5 + y = -3, and y = 2.
You should check to determine whether x=2 is also correct. If it is, what is the corresponding y value?
For the answer to the question above, this is a right triangle problem using the tangent function.
<span>Tan(x) = Opposite (O) / Adjacent (A) </span>
<span>x = 40 degrees </span>
<span>A = 30 ft </span>
<span>Solve for O </span>
<span>O= Tan (x) * A </span>
<span>O = Tan (40) * 30 </span>
<span>Use your calculator or whatever method to get the tangent of 40 degrees (which is .84) </span>
<span>O = .84 * 30 </span>
<span>O = 25.2 Ft</span>
9514 1404 393
Answer:
23) 35.77 in²
25) 48.19 cm²
Step-by-step explanation:
Use the appropriate area formula with the given information.
__
23) The area of a triangle is given by the formula ...
A = 1/2bh . . . . . base b, height h
A = 1/2(9.8 in)(7.3 in) = 35.77 in²
__
25) The area of a parallelogram is given by the formula ...
A = bh . . . . . . base b, height h
A = (7.9 cm)(6.1 cm) = 48.19 cm²
_____
The <em>height</em> in each figure is <em>measured perpendicular to the base</em>. This tells you that the length 10.6 cm of the diagonal side of the triangle is not relevant to finding the area.
Answer:
A. Repeat the simulation several more times
Step-by-step explanation:
The purpose of the simulation model is to represent the effectivity of the passes.
The proportion of successful passes is 60%.
As we have 10 digits available, 6 (digits from 0 to 5) are used for the outcome "the pass is completed" and 4 (digits 6, 7, 8, and 9) to represent the outcome "the pass is not completed". This is correct, as it represents a probability of 60% of having a successful pass.
But to have a representative distribution of the possible and probable results, the simulation have to run enough times to have a stable distribution of the results.
