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3 years ago

What are the answers plz help me

Mathematics

1 answer:

Serga [27]3 years ago

8 0

For number 3 it would be |-10| and |10|.

Number 5a is supposed to <, because -1 is greater than -7 when you look at the line graph. The same goes for 5b. 5d is >, because 0 is always greater than -1 and it shows that on the line graph that you have there. 5e is =.

I don't see anything else wrong though. Just the ones I listed.

Hope that helps!

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write a possible point slope form of the equation of the line that passes through the points (4,4) and (3,-2)?

Mashutka [201]

m=-2-4/3-4=-6/-1=6

y-4=6(x-4)

y=6x-20

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3 years ago

The container that holds the water for the football team is

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Hope this helps.

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3 years ago

6⋅[(32−8)÷4+2] What is the answer to this expession?

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Answer:

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3 years ago

Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

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3 years ago

What value of x would result in the numerical value of zero in the expression 7+x+(−10) ?

MAXImum [283]

Answer:

Step-by-step explanation:

7 plus three is 10, adding -10 to that equals zero.

4 0

3 years ago