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Angelina_Jolie [31]

3 years ago

13

The bottle of juice says that has three times as much orange juice is apple juice. If the bottle contains 64 fluid ounces, how m

any ounces of orange juice does it contain.

1 answer:

nikitadnepr [17]3 years ago

5 0

Answer:

192

Step-by-step explanation:

64

× 3

______

192

multiply sixty-four with three

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8x+4(x-3)=4(6x+4)-4 please help

kvasek [131]

Answer:

x = -2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

8x + 4(x - 3) = 4(6x + ) -4

8x +(4)(x) + (4)(-3) = (4)(6x) + (4)(4) + -4 (distribute)

8x + 4x + -12 = 24x + 16 + -4

(8x) + (4x) +(-12) = (24x) + (16 + -4) (combine like terms)

12x + -12 = 24x + 12

12x -12 = 24x + 12

Step 2: Subtract 24x from both sides.

12x -12 -24x = 24x + 12 -24x

-12x -12 = 12

Step 3: Add 12 to both sides.

-12x - 12 + 12 = 12 + 12

-12x = 24

Step 4: Divide both sides by -12.

-12x/-12 = 24/-12 <u>x = -2</u>

HOPE THIS HELPED!!!

5 0

3 years ago

Jonas solved an equation incorrectly, as shown below:

alexandr1967 [171]

So first he has to divide both sides by 8
wat
he multiplied the right side by 8 but divided left by 8
that is wrong

answer is 4th option
divid not divide 56 by 8

6 0

3 years ago

Read 2 more answers

If the point (2,5) is on the graph of an equation, which statement must be

Hunter-Best [27]

Answer: D

Step-by-step explanation:

The values x = 2 and y = 5 make the equation true.

4 0

3 years ago

Rationalise the denominator of:<br>1/(√3 + √5 - √2)

Paul [167]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm :\longmapsto\:\dfrac{1}{ \sqrt{3} + \sqrt{5} - \sqrt{2} }$

can be re-arranged as

$\rm :\longmapsto\:\dfrac{1}{ \sqrt{3} - \sqrt{2} + \sqrt{5} }$

$\rm \: = \: \dfrac{1}{( \sqrt{3} - \sqrt{2} ) + \sqrt{5} }$

On rationalizing the denominator, we get

$\rm \: = \: \dfrac{1}{( \sqrt{3} - \sqrt{2} ) + \sqrt{5} } \times \dfrac{( \sqrt{3} - \sqrt{2} ) - \sqrt{5} }{( \sqrt{3} - \sqrt{2} ) - \sqrt{5} }$

We know,

$\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) = {x}^{2} - {y}^{2} \: }}$

So, using this, we get

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{ {( \sqrt{3} - \sqrt{2} )}^{2} - {( \sqrt{5}) }^{2} }$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{3 + 2 - 2 \sqrt{6} - 5}$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{5 - 2 \sqrt{6} - 5}$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{ - 2 \sqrt{6}}$

$\rm \: = \: \dfrac{ - ( - \sqrt{3} + \sqrt{2} + \sqrt{5}) }{ - 2 \sqrt{6}}$

$\rm \: = \: \dfrac{- \sqrt{3} + \sqrt{2} + \sqrt{5}}{2 \sqrt{6}}$

On rationalizing the denominator, we get

$\rm \: = \: \dfrac{- \sqrt{3} + \sqrt{2} + \sqrt{5}}{2 \sqrt{6}} \times \dfrac{ \sqrt{6} }{ \sqrt{6} }$

$\rm \: = \: \dfrac{- \sqrt{18} + \sqrt{12} + \sqrt{30}}{2 \times 6}$

$\rm \: = \: \dfrac{- \sqrt{3 \times 3 \times 2} + \sqrt{2 \times 2 \times 3} + \sqrt{30}}{12}$

$\rm \: = \: \dfrac{- 3\sqrt{2} + 2 \sqrt{3} + \sqrt{30}}{12}$

Hence,

$\boxed{\tt{ \rm \dfrac{1}{ \sqrt{3} + \sqrt{5} - \sqrt{2} } =\dfrac{- \sqrt{3 \times 3 \times 2} + \sqrt{2 \times 2 \times 3} + \sqrt{30}}{12}}}$

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<h3><u>More Identities to </u><u>know:</u></h3>

$\purple{\boxed{\tt{ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}}}}$

$\purple{\boxed{\tt{ {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}}}}$

$\purple{\boxed{\tt{ {(x + y)}^{3} = {x}^{3} + 3xy(x + y) + {y}^{3}}}}$

$\purple{\boxed{\tt{ {(x - y)}^{3} = {x}^{3} - 3xy(x - y) - {y}^{3}}}}$

$\pink{\boxed{\tt{ {(x + y)}^{2} + {(x - y)}^{2} = 2( {x}^{2} + {y}^{2})}}}$

$\pink{\boxed{\tt{ {(x + y)}^{2} - {(x - y)}^{2} = 4xy}}}$

6 0

3 years ago

When the function below is graphed, how many x-intercepts does it have? y = 4x2 + 5x + 2

Olenka [21]

B it would have 0.......

3 0

3 years ago

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