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Marat540 [252]
3 years ago
10

How many​ one-to-one correspondences are there between two sets with 5 elements​ each?

Mathematics
1 answer:
Fittoniya [83]3 years ago
7 0
1st element can be matched with 5
2nd element can be matched with 4
3rd element can be matched with 3
etc.
Total number of correspondences = 5*4*3*2*1 = 120
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amm1812

Answer:

$286

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liraira [26]

Answer:

option 1 and 4

Step-by-step explanation:

The elimination method should be used when there are two variables with the same number in front of them but different signs.

In the first system, the first equation has -8y while the second one has 8y.

Both equations have an 8y with different signs therefore using the elimination method would be most logical.

In the fourth system, the first equation has a -4x while the second one has 4x.

Both equations have 4x with different signs therefore using the elimination method would be most logical

Reasons it can't be the other options :

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In the third system y is defined by an expression therefore using the substitution method is the most logical approach.

8 0
2 years ago
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viktelen [127]
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3 years ago
What is the equation of a line that passes through the point (8, −2) and is parallel to the line whose equation is 3x + 4y = 15?
Inga [223]

Answer:

Step-by-step explanation:

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7 0
3 years ago
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3 years ago
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