What property is illustrated in the question 9+ 13=13+9

find the slope-intercept form of the line whose slope os 4 and that passes through the point (-9,12)

Trava [24]

Answer:

y = 4x+48

Step-by-step explanation:

Slope intercept form is y=mx+b. We already know the value for m(4), so we can plug in the x and y coordinates for x and y in the equation. This gives us 12=4(-9)+b. Solve for b to get 48

7 0

3 years ago

What is the domain of g?<br><br><br><br><br>

wariber [46]

Answer:

The answer is -9,9 Its funny cuz I just did this problem on Khan academy

Step-by-step explanation:

Can I get brainliest

5 0

3 years ago

Read 2 more answers

2). Bill has twice as many candies as Fred. Tim has 3 fewer than 3 times as many candles as Fred.

sasho [114]

Step-by-step explanation:

<h2>Answer:-</h2>

$\tt{Let \ the \ candies \ taken \ by \ Fred \ be \ x.}$

Now, let's Solve!

So, according to Question,

Bill = 2x

Tim = 3x-3

Total Candies = 177.

$\bf{x+2x+3x-3=177}$

Totalling x,

$\bf{6x-3=177}$

$\bf{6x=177+3}$

$\bf{6x = 180}$

$\boxed{\sf{x = 30}}$

So, Fred has 30 candies.

Bill's Candies = 2×30 = 60 Candies

Tim's Candies = 3×30-3 = 90-3 = 87 Candies.

Hope it helps :)

7 0

2 years ago

Why were Samaritans disliked by the Jews at the time?

arsen [322]

Answer: they had a bad reputation

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Set up the integral that represents the arc length of the curve f(x) = ln(x) + 5 on [1, 3], and then use Simpson's Rule with n =

marta [7]

Answer:

The integral for the arc of length is:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx$

By using Simpon’s rule we get: 1.5355453

And using technology we get: 2.3020

The approximation is about 33% smaller than the exact result.

Explanation:

The formula for the length of arc of the function f(x) in the interval [a,b] is:

$\displaystyle\int_a^b \sqrt{1+[f'(x)]^2}dx$

We need the derivative of the function:

$f'(x)=\frac{1}{x}$

And we need it squared:

$[f'(x)]^2=\frac{1}{x^2}$

Then the integral is:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx$

Now, the Simposn’s rule with n=4 is:

$\displaystyle\int_a^b g(x)}dx\approx\frac{\Delta x}{3}\left( g(a)+4g(a+\Delta x)+2g(a+2\Delta x) +4g(a+3\Delta x)+g(b) \right)$

In this problem:

$a=1,b=3,n=4, \displaystyle\Delta x=\frac{b-a}{n}=\frac{2}{4}=\frac{1}{2},g(x)= \sqrt{1+\frac{1}{x^2}}$

So, the Simposn’s rule formula becomes:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\\\approx \frac{\frac{1}{3}}{3}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{1}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(1+\frac{2}{2}\right)^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{3}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)$

Then simplifying a bit:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx \approx \frac{1}{9}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(\frac{3}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(2\right)^2}} +4\sqrt{1+\frac{1}{\left(\frac{5}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)$

Then we just do those computations and we finally get the approximation via Simposn's rule:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\approx 1.5355453$

While when we do the integral by using technology we get: 2.3020.

The approximation with Simpon’s rule is close but about 33% smaller:

$\displaystyle\frac{2.3020-1.5355453}{2.3020}\cdot100\%\approx 33\%$

8 0

2 years ago