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3 years ago

Which parent funtion is f(x)=x^2

Mathematics

1 answer:

Darina [25.2K]3 years ago

5 0

I believe it is C. The quadratic function.

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Write a division expression that has a negative solution.

Anon25 [30]

Answer:

3/-3=-1

Step-by-step explanation:

any number divided by a negative number gives a negative answer

8 0

2 years ago

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

I will try to give as many details as possible.

First of all, I just would like to say:

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Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! （＊＾Ｕ＾）人（≧Ｖ≦＊）/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

3 years ago

Use elimination to solve the system of equations. 3x – 5y = –9 x + 2y = 8

nalin [4]

Answer:

x=2

y=3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Santa and his elves had a workshop that allowed them to produce 22{,}912{,}546{,}99222,912,546,99222, comma, 912, comma, 546, co

zvonat [6]

Answer: 180 times

Step-by-step explanation:

Given the following :

Production capacity of old workshop :22,912,546,992 toys per year

Production capacity of new workshop:

4,134,232,638,937 toys

Approximately how many times as many toys can the new workshop produce each year compared to the old workshop?

Production capacity of new workshop / production capacity of old workshop

= 4,134,232,638,937 / 22,912,546,992

= 180.435

= 180 ( nearest whole number)

3 0

3 years ago

The angles below are supplementary. What is the value of x? 5 7.5 15 30

OLEGan [10]

Answer:

x=30

Step-by-step explanation:

The two angles are supplementary. They add to 180

4x+20 + 40 =180

Combine like terms

4x+60 =180

Subtract 60 from each side

4x+60-60 = 180-60

4x = 120

Divide each side by 4

4x/4 = 120/4

x = 30

7 0

3 years ago

Read 2 more answers