One way to do this is to consider what the average of these integers is. It would be 519/6, or 86.5. This means the six integers are "centered" around 86.5: they would be 84, 85, 86, 87, 88, and 89 (there are three numbers greater than 86.5 and three less than 86.5 in this list).
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Divide the figure into two parts, a triangle and a square
TRIANGLE
the base (b) = 5 cm
the height (h) = 4 cm
Calculate the area of the triangle
a = 1/2 × b × h
a = 1/2 × 5 × 4
a = 20/2
a = 10
The area of the triangle is 10 cm²
SQUARE
the side (s) = 5 cm
Calculate the area of the square
a = s²
a = 5²
a = 25
The area of the square is 25 cm²
THE AREA OF THE FIGURE
a figure = a of triangle + a of square
a figure = 10 + 25
a figure = 35
The area of the figure is 35 cm²
Answer:
52°
Step-by-step explanation:
In the figure attached, Circle A is shown. There we can see that:
∠BC + ∠CD = ∠BAD
We know that Arc BC measures 96° and arc BAD measures 148°. Replacing this data into the equation and solving for Arc CD, we get:
96° + ∠CD = 148°
∠CD = 148° - 96°
∠CD = 52°
