Answer:
a,c
Step-by-step explanation:
if Jen covered m miles.

5x + 2y = 22
10x + 9y = 59
so now we need to either eliminate the y or the x and we need to multiply both numbers by something so that they will be the same and we can add or minus them.
so here I will eliminate x because it's easier
we multiply the top equation by 2 and the bottom equation by 1 and we get
10x + 4y = 44
10x + 9y = 59
so now we can see that the number of x's are the same and we can just find the DIFFERENCE between the two equations if it was -10x and 10x we would ADD
= 5y = 15
notice that the x'a have cancelled each other out
now we divide both sides by 5 so
y=3
now we have y, we need to substitute it into one of the original equations, doesn't matter which one. I'm going to do the first one.
5x + 2y = 22
5x + 2(3)=22
5x + 6 = 22
now minus 6 from both sides
5x = 16
divide both sides by 5
x = 3.2
we have our answers but to be sure we need to just substitute the values for x and y into BOTH original equations.
5x + 2y = 22
= 16 + 6 = 22
10x + 9y = 59
= 32 + 27 =59
Tadaa!! and there you have it
y = 3
x = 3.2
hope this helped :)
Answer:

Step-by-step explanation:
Mark got 54 out of 66 correct in his test.
We need to find what fraction of the marks did he get correct,
Total number of questions = 66
Total number of correct answers = 54

<span>
4. The x-coordinate of the solution is 9.</span><span>
5. The y-coordinate of the solution is −8 .</span><span>
6.The ordered pair that is the solution to the system lies in Quadrant IV .</span><span>
Proof:
Solve the following system:
{4 x + 3 y = 12 | (equation 1)
{2 x + 3 y = -6 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x + 3 y = 12 | (equation 1)
{0 x+(3 y)/2 = -12 | (equation 2)
Multiply equation 2 by 2/3:
{4 x + 3 y = 12 | (equation 1)
{0 x+y = -8 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 36 | (equation 1)
{0 x+y = -8 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 9 | (equation 1)
{0 x+y = -8 | (equation 2)
Collect results:
Answer: {x = 9 , y = -8</span>
Answer:
15
Step-by-step explanation:
The range from Q1 to Q3 is the interquartile range (IQR).
The interquartile range is the difference between the third and first quartiles.
The third quartile is 17.5.
The first quartile is 2.5.
The interquartile range = <u>17.5 - 2.5</u> = 15.